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3 years ago

For the balanced equation shown below, how many grams of CoHS reacted, if 56.5 grams of H20 are produced?

Chemistry

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

c) 17.8 mol

Explanation:

big brain

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6. You have $50.00. You buy a CD for $15.50. You sell it to your friend for $12.00. He doesn't

kompoz [17]

Answer: the answer is that you made $2

Explanation:

4 0

3 years ago

How many elements are in “CO2”

aleksandr82 [10.1K]

2 elements, the C is Carbon and the O is oxygen.

3 0

3 years ago

Read 2 more answers

Kemmi Major does some experimental work on the combustion of sucrose: C12H22O11(s) 12 O2(g) → 12 CO2(g) 11 H2O(g) She burns a 0.

Pavlova-9 [17]

Answer: $5.81\times 10^6J/mol$

Explanation:

Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

$C_{12}H_{22}O_{11}(s)+12O_2\rightarrow 12CO_2(g)+11H_2O(g)$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles$

Thus $1.577\times 10^{-4}moles$ of sucrose releases = 916.6 J of heat

1 mole of sucrose releases = $\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J$ of heat

Thus ∆H value for the combustion reaction is $5.81\times 10^6J/mol$

6 0

4 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 9.50 MJ 9

tensa zangetsu [6.8K]

Answer:

709415.584 g

Explanation:

This is a heat capacity problem. We use the formula below to calculate.

Q=mcΔT

where Q is the quantity of heat

m is the mass of substance

ΔT is the change in temperature of substance( T2-T1).

Q= 9.5MJ = 9.5*10^(6}J

C.P = 30.8J/(K.mol)

temperature of sodium increases by 10°C which means our final temperature in kelvin T2 will be 510K

initial temperature T1= 500K

m= Q/[c (T2-T1)]

m= 9.5*10^(6}/ {30.8(510-500)]

m= 30844.156 mol of Na

Converting to grams we multiply by the molar mass of Na.

molar mass of Na = 23

mass of Na= 30844.156 *23

=709415.584 g

7 0

3 years ago

On a cool, rainy day, the barometric pressure is 698 mmHg. Calculate the barometric pressure in centimeters of water (cmH2O). De

lesantik [10]

Answer:

Barometric pressure is 942.3 cm of column of water.

Explanation:

We can measure barometric pressure by measuring the height h of a column of fluid (this column of fluid exerts the same pressure as the column of air of which we are measuring pressure) using the following formula:

$P = \rho*g*h\\$

Where ρ is the density of the fluid used and g the acceleration of gravity.

Knowing that both the column of mercury (to match units, we know that 698 mmHg are the same as 69.8 cmHg) and the column of water are representing the same pressure, we can match expressions and find h for the column of water:

$\rho_{Hg} *g*h_{Hg} =\rho_{Water} *g*h_{Water}\\ \\h_{Water}=\frac{rho_{Hg} *g*h_{Hg}}{\rho_{Water} *g} = \frac{13.5g/mL *9.8m/s^{2} *69.8cm}{1g/mL *9.8m/s^{2}}=942.3 cmH_{2}O$

7 0

3 years ago