Answer is: the mass of solute in the solution is 110 grams.
c(Na₂CO₃) = 0.730 M; molarity of sodium carbonate solution.
V(Na₂CO₃) = 1.421 L; volume of solution.
n(Na₂CO₃) = c(Na₂CO₃) · V(Na₂CO₃).
n(Na₂CO₃) = 0.73 mol/L · 1.421 L.
n(Na₂CO₃) = 1.037 mol; amount of solute.
M(Na₂CO₃) = 106 g/mol; molar mass of sodium carbonate.
m(Na₂CO₃) = n(Na₂CO₃) · M(Na₂CO₃).
m(Na₂CO₃) = 1.037 mol · 106 g/mol.
m(Na₂CO₃) = 110 g; mass of sodium carbonate.