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coldgirl [10]
3 years ago
5

Jimmy applied the distributive property to write the equation below.

Chemistry
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

D) Jimmy wrote two expressions that are not equivalent.

Explanation:

24 + 6 = 6 (4 + 2)

These are not equivalent. I got it right.

damaskus [11]3 years ago
3 0

Answer:

Jimmy wrote two expressions that are not equivalent

Explanation:

24+6=30 while 6(4+2) equals 36 because if you distribute the 6 to 4 (which equals 24) then the 6 to 2 (which equals 12) and add 24 and 12 together, you get 36. So, 24+6  =/= 6(4+2). Hopefully this is correct!

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Elis [28]

Answer:

I believe the answer is Molten

Explanation:

I did that quiz and got 100% :)

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3 years ago
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What is the mass of HF produced by three reaction of 3.0 10 to the 23 molecules of H2 with excess F2
JulijaS [17]

Answer:

It is 20. g HF

Explanation:

H2 + F2 ==> 2HF  ...  balanced equation

Since the question is asking us to find the mass of product formed, we will want to first convert the molecules of H2 into moles of H2 (we could do this at the end of the calculations, but it's just as easy to do it now).

moles of H2 present (using Avogadro's number):  

3.0x1023 molecules H2 x 1 mole H2/6.02x1023 molecules = 0.498 moles H2

From the balanced equation, we see that 1 mole H2 produces 2 moles HF.  Therefore, we can now find the theoretical mass of HF produced from 0.498 moles H2:

0.498 moles H2 x 2 moles HF/1 mol H2 = 0.996 moles HF formed.

The molar mass of HF = 20.01 g/mole, thus...

0.996 moles HF x 20.01 g/mole = 19.93 g HF = 20. g HF formed (to 2 significant figures)

6 0
2 years ago
Identify two sources of heat that melt rocks beneath Earth's surface.
elena55 [62]

Answer:

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8 0
2 years ago
What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

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2 years ago
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Mashcka [7]

HEY DEAR..

The particles of light known as photon.

HOPE ITS HELPFULL

6 0
2 years ago
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