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amm1812
3 years ago
6

Formula for "barium oxide"

Chemistry
1 answer:
Harman [31]3 years ago
4 0
The answer is BaO
hope this helpsssss
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How many atoms are in 3.20 moles of carbon
DIA [1.3K]

Answer:

19.264×10^{23} atoms are present in 3.2 moles of carbon.

Explanation:

It is known that one mole of each element is composed of Avagadro's number of atoms. This is same for all the elements in the periodic table.

So, as 1 mole of any element = Avagadro's number of atoms = 6.02×10^{23} atoms

It is as simple as understanding a dozen of anything is equal to 12 pieces of that object.

As here the moles of carbon is given as 3.20 moles, the number of atoms in this mole can be determined as below.

1 mole of carbon = 6.02 ×10^{23} atoms

Then, 3.20 moles of carbon = 3.20 × 6.02 ×10^{23} atoms

Thus, 19.264×10^{23} atoms are present in 3.2 moles of carbon.

6 0
3 years ago
Types of isomers possible for ch3 ch2 ch2 ch3
puteri [66]

Answer:

It has two isomers; n-butane and isobutane. Here n-butane is a straight-chain compound with four carbon atoms bonded with single covalent bonds. Explanation: Butane is an alkane with four carbon atoms so molecular formula is C4H10.

Explanation:

4 0
2 years ago
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AnnZ [28]
Here you are looking on the Free Body diagram of a net force of 0N in both the x and y-directions.  the only ones that has that condition met is A and C.
4 0
3 years ago
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Katarina [22]

Answer:

a covalent would be the two that are nonmetals

7 0
3 years ago
A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the
Sveta_85 [38]

Answer:

The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

Explanation:

Using the formula

Ca Va = Cb Vb

Cb = 0.32 M

Vb = 50 mL = 50/1000 = 0.050L

Ca = 0.5 M

Va =?

Substituting for Va in the equation, we obtain:

Va = Cb Vb / Ca

Va = 0.32 * 0.05 / 0.5

Va = 0.016 / 0.5

Va = 0.032 L

The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

6 0
3 years ago
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