0.53313648 feet = 16.25cm
Answer:
E° = 1.24 V
Explanation:
Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)
According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:
Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an
E° = 0.80 V - (-0.44 V) = 1.24 V
<h3>
Answer:</h3>
5.6 Liters
<h3>
Explanation:</h3>
- N.T.P. refers to the standard temperature and pressure (S.T.P).
We need to know that;
- One mole of a gas occupies a volume of 22.4 liters at N.T.P.
In this case;
We have 11 g of CO₂
But, 1 mole of CO₂ occupies 22.4 l at N.T.P.
1 mole of CO₂ = 44 g
Therefore;
44 g of CO₂ = 22.4 liters
What about 11 g ?
= (11 g × 22.4 l)÷ 44 g
= 5.6 l
Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.
One mole (abbreviated mol) is equal to 6.022×1023 molecular entities (Avogadro's number), and each element has a different molar mass depending on the weight of 6.022×1023 of its atoms (1 mole). The molar mass of any element can be determined by finding the atomic mass of the element on the periodic table.
