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anygoal [31]
3 years ago
6

If the diameter of a men’s basketball is 10 inches and a women’s is 9 inches, what is the approximate difference of their volume

s?
Mathematics
2 answers:
Mashutka [201]3 years ago
7 0

Answer:

141.89526818714 cubic inches

Step-by-step explanation \

Vm = Volume of the men's basketball

Vm = (4/3)*pi*r^3

Vm = (4/3)*pi*(5)^3 ... diameter = 10 --> radius = 10/2 = 5

Vm = 523.598775598299 cubic inches

Vw = Volume of the women's basketball

Vw = (4/3)*pi*r^3

Vw = (4/3)*pi*(4.5)^3 ... diameter = 9 --> radius = 9/2 = 4.5

Vw = 381.70350741116 cubic inches

Difference in volume = Vm - Vw

Difference in volume = 523.598775598299 - 381.70350741116

Difference in volume = 141.89526818714 cubic inches

This result is approximate

Over [174]3 years ago
5 0

Answer:

1

Step-by-step explanation:

10-9

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2 years ago
3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the
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Answer:

h= 1500\,*\,sin(43^o)

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)

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3 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
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Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

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Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

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Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
Help with this one too, please.
OLEGan [10]

5 units left and 7 units up

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