15+3=18km/hour
Think about it like this. The boat is going 15 faster than the river, and the river is going 3 faster than the bank, so the boat is going 18 faster than the river bank
The acceleration of a 0.90 g drop of blood in the fingertips at the bottom of the swing is the sum of the acceleration of the movement of the finger and the acceleration of gravity. In this case, this is different when the finger goes down, since the acceleration now becomes the difference between the two.
Answer;
D. where two plates collide
Explanation;
-Subduction zones are plate tectonic boundaries where two plates converge, and one plate is thrust beneath the other. This process results in geohazards, such as earthquakes and volcanoes.
-Subduction zone volcanism occurs where two plates are converging on one another. One plate containing oceanic lithosphere descends beneath the adjacent plate, thus consuming the oceanic lithosphere into the earth's mantle. This on-going process is called subduction.
Explanation:
Terminal velocity is given by:
![v_t=\sqrt{\frac{2mg}{\rho C_dA}}](https://tex.z-dn.net/?f=v_t%3D%5Csqrt%7B%5Cfrac%7B2mg%7D%7B%5Crho%20C_dA%7D%7D)
Here, m is the mass of the falling object, g is the gravitational acceleration,
is the drag coefficient,
is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:
![A=\frac{A_s}{2}=\frac{930cm^2}{2}=465cm^2\\465cm^2*\frac{1m^2}{10^4cm^2}=0.0465m^2\\560g*\frac{1kg}{10^3g}=0.56kg](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BA_s%7D%7B2%7D%3D%5Cfrac%7B930cm%5E2%7D%7B2%7D%3D465cm%5E2%5C%5C465cm%5E2%2A%5Cfrac%7B1m%5E2%7D%7B10%5E4cm%5E2%7D%3D0.0465m%5E2%5C%5C560g%2A%5Cfrac%7B1kg%7D%7B10%5E3g%7D%3D0.56kg)
Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is
.
![v_t=\sqrt{\frac{2(0.56kg)(9.8\frac{m}{s^2})}{(1.28\frac{kg}{m^3}(1)(0.0465m^2)}}\\v_t=13.58\frac{m}{s}](https://tex.z-dn.net/?f=v_t%3D%5Csqrt%7B%5Cfrac%7B2%280.56kg%29%289.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%7D%7B%281.28%5Cfrac%7Bkg%7D%7Bm%5E3%7D%281%29%280.0465m%5E2%29%7D%7D%5C%5Cv_t%3D13.58%5Cfrac%7Bm%7D%7Bs%7D)
Without drag contribution the motion of the person is an uniformly accelerated motion, thus:
![v_f^2=v_o^2+2gh\\v_f=\sqrt{2gh}\\v_f=\sqrt{2(9.8\frac{m}{s^2})(5m)}\\v_f=9.9\frac{m}{s}](https://tex.z-dn.net/?f=v_f%5E2%3Dv_o%5E2%2B2gh%5C%5Cv_f%3D%5Csqrt%7B2gh%7D%5C%5Cv_f%3D%5Csqrt%7B2%289.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%285m%29%7D%5C%5Cv_f%3D9.9%5Cfrac%7Bm%7D%7Bs%7D)
Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V