6x10^8 kg<br> —————<br> 2x10^4 m^3

An AC power source has an rms voltage of 120 V and operates at a frequency of 60.0 Hz. If a purely inductive circuit is made fro

Dmitrij [34]

Answer:

(a) 17634.24 Ω

(b) 0.0068 A

Explanation:

(a)

The formula for inductive inductance is given as

X' = 2πFL................... Equation 1

Where X' = inductive reactance, F = frequency, L = inductance

Given: F = 60 Hz, L = 46.8 H, π = 3.14

Substitute into equation 1

X' = 2(3.14)(60)(46.8)

X' = 17634.24 Ω

(b)

From Ohm's law,

Vrms = X'Irms

Where Vrms = Rms Voltage, Irms = rms Current.

make Irms the subject of the equation

Irms = Vrms/X'...................... Equation 2

Given: Vrms = 120 V, X' = 17634.24 Ω

Substitute into equation 2

Irms = 120/17634.24

Irms = 0.0068 A

5 0

3 years ago

Select the correct answer.

aleksklad [387]

A. Alternating current

4 0

3 years ago

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newt

Salsk061 [2.6K]

1.8x10 sqaured newtons for all plato users

5 0

3 years ago

Read 2 more answers

Suppose light from a 632.8 nm helium-neon laser shines through a diffraction grating ruled at 520 lines/mm. How many bright line

Leya [2.2K]

Answer:

1 bright fringe every 33 cm.

Explanation:

The formula to calculate the position of the m-th order brigh line (constructive interference) produced by diffraction of light through a diffraction grating is:

$y=\frac{m\lambda D}{d}$

where

m is the order of the maximum

$\lambda$ is the wavelength of the light

D is the distance of the screen

d is the separation between two adjacent slit

Here we have:

$\lambda=632.8 nm = 632.8\cdot 10^{-9} m$ is the wavelength of the light

D = 1 m is the distance of the screen (not given in the problem, so we assume it to be 1 meter)

$n=520 lines/mm$ is the number of lines per mm, so the spacing between two lines is

$d=\frac{1}{n}=\frac{1}{520}=1.92\cdot 10^{-3} mm = 1.92\cdot 10^{-6} m$

Therefore, substituting m = 1, we find:

$y=\frac{(632.8\cdot 10^{-9})(1)}{1.92\cdot 10^{-6}}=0.330 m$

So, on the distant screen, there is 1 bright fringe every 33 cm.

6 0

3 years ago

Stairway must have uniform riser height and tread depth; variations in riser height or tread depth shall not be over _______ inc

alexandr1967 [171]

Answer:

$\frac{3}{8} inches$

Explanation:

the variations in riser height or tread depth should not be grater than $\frac{3}{8} inches$ that is equal to 9.5 mm but the maximum riser height should be the $\frac{81}{4} inch$ but variation in riser height should not exceed to $\frac{3}{8} inches$ . The minimum riser height should be 7 inches which is equal to the 178 mm

5 0

3 years ago

6x10^8 kg ————— 2x10^4 m^3