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a_sh-v [17]
2 years ago
10

Two blocks, of mass m and 2m, are initially at rest on a horizontal frictionless surface. A force F is exerted individually on e

ach block, as shown above. The graph shows how F varies with time t. Which block has the greatest average power provided to it between t = 0 s and t = 3 s?
Physics
1 answer:
Anon25 [30]2 years ago
7 0

The block has the greatest average power provided is bock m.

<h3>What is instantaneous power?</h3>
  • This is the product of force and velocity exerted on an object.

Mathematically instantaneous power is calculated as;

P = Fv

where;

  • F is the applied force
  • v is the velocity

Both blocks (m and 2m) will experience the same force but different velocity.

The smaller block (m) will experience greater velocity.

Thus, the block has the greatest average power provided is bock m.

Learn more about instantaneous power here: brainly.com/question/8893970

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The English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from Engl
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Answer:

a.) 20.4 h

b.) 3.46 km/h

Explanation:

Given that an English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from England to France. The current across this portion of the English Channel runs at about 2 km/h east to west.

a.) If a swimmer has a relative velocity to the shore of 3 km/h north to south, The resultant velocity (Vr) will be achieved by using Pythagoras theorem  

Vr = \sqrt{2^{2} + 3^{2}  }

Vr = \sqrt{4 + 9}

Vr = \sqrt{12}

Vr = 3.46 m/s

To get how long it take her to cross the 35 km distance, Let us first find acceleration by using third equation of motion.

V^{2} = U^{2} + 2aS

Where U = 0

Substitute all the parameters into the equation

3.46^{2} = 2 x a x 35

11.97 = 70a

a = 11.97/70

a = 0.17 km/h^2

The time can be found by using equation

V = U + at

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3.46 = 0.17t

t = 3.46/0.17

t = 20.35h

b. What must be her velocity relative to the water if she has a velocity of 3 km/h north to south relative to the shore?

her velocity relative to the water will be

Vr = \sqrt{2^{2} + 3^{2}  }

Vr = \sqrt{4 + 9}

Vr = \sqrt{12}

Vr = 3.46 m/s

3 0
3 years ago
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