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a_sh-v [17]
2 years ago
10

Two blocks, of mass m and 2m, are initially at rest on a horizontal frictionless surface. A force F is exerted individually on e

ach block, as shown above. The graph shows how F varies with time t. Which block has the greatest average power provided to it between t = 0 s and t = 3 s?
Physics
1 answer:
Anon25 [30]2 years ago
7 0

The block has the greatest average power provided is bock m.

<h3>What is instantaneous power?</h3>
  • This is the product of force and velocity exerted on an object.

Mathematically instantaneous power is calculated as;

P = Fv

where;

  • F is the applied force
  • v is the velocity

Both blocks (m and 2m) will experience the same force but different velocity.

The smaller block (m) will experience greater velocity.

Thus, the block has the greatest average power provided is bock m.

Learn more about instantaneous power here: brainly.com/question/8893970

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During a workout, the football players at State U ran up the stadium stairs in 61 s. The stairs are 130 m long and inclined at a
NeTakaya

Answer:

  P = 1097 Watt

Explanation:

given,

length of stairs, L = 130 m

inclination with horizontal,θ = 30°

mass of the football player = 105 Kg

time = 61 s

we know,

Power = \dfrac{work}{time}

Work = change in Potential energy

 h = L sin 30°

 h = 130 x 0.5

 h = 65 m

W = m g h

W = 105 x 9.8 x 65

W = 66885 J

now,

P = \dfrac{66885}{61}

  P = 1097 Watt

hence, the power output on the way is 1097 W

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Answer:

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What is the entropy change associated with the expansion of one mole of an ideal gas from an initial volume of v to a final volu
Kaylis [27]

Answer:

ΔS = 7.618 J/K

Explanation:

The entropy change associated to an isothermal process is:

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We can calculate Q (heat) how:

Q = nRTln(\frac{Vf}{Vi})

   Where Vf = 2.5v

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Then

Q = nRTln(2.5)

ΔS = \frac{nRTln(2.5)}{T}

ΔS = (1)(8.314)ln(2.5)

ΔS = 7.618 J/K

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