Answer:
0.010 m
Explanation:
So the equation for a pendulum period is:
where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:
![1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\](https://tex.z-dn.net/?f=1.99%20s%20%3D%202%283.14%29%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D%7D%5C%5C)
Evaluate the multiplication in front
![1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}](https://tex.z-dn.net/?f=1.99%20s%20%3D%206.28%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8m%5Cbackslash%20s%5E2%7D)
Divide both sides by 6.28
![0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}](https://tex.z-dn.net/?f=0.317%20s%3D%20%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D%7D)
Square both sides
![0.100 s^2= \frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.100%20s%5E2%3D%20%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Multiply both sides by m/s^2 (the s^2 will cancel out)
Now now let's find the length when it's two seconds
![2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}](https://tex.z-dn.net/?f=2.00%20s%20%3D%206.28%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8m%5Cbackslash%20s%5E2%7D%7D)
Divide both sides by 6.28
![0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.318%20s%20%3D%20%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Square both sides
![0.101 s^2 = \frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.101%20s%5E2%20%3D%20%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)
![0.994 m = L](https://tex.z-dn.net/?f=0.994%20m%20%3D%20L)
So to find the difference you simply subtract
0.984 - 0.994 = 0.010 m
Most reactions are exothemic. If the forward reaction of an equilibrium reaction is exothemic then the reverse reaction must be endothermic.
If a system in equilibrium is heated, it will move in exothermic direction to give out heat energy.
Answer:
Option 4
Explanation:
During heating actually heat transfer takes place from a body at higher temperature to a body at lower temperature and the heat transfer takes place until both attain the same temperature
Therefore heat transfer depends on the temperature of the systems
Now while comparing the thermal energies of the systems, if both the systems have same mass then the system which is at higher temperature has greater thermal energy when compared to the system which is at lower temperature
So in this case assuming that both the systems have same mass then the energy will leave the system with greater thermal energy and go into the system with less thermal energy as the system with greater thermal energy in this case will be at higher temperature and we are considering this assumption because thermal energy not only depends on temperature but also depends on mass of the system
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU