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2 years ago

3. Suppose you take a pendulum with length L and mass m having a period T to a

Physics

1 answer:

natta225 [31]2 years ago

6 0

(C)

Explanation:

$t = 2\pi \sqrt{ \frac{l}{g} }$

If g is only 1/6 on another planet, then

$t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } = 2\pi \sqrt{ \frac{6l}{g} }$

$= \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4 \times t(on \: earth)$

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Which element of a valid contract is established by getting the signatures of all parties?

sweet [91]

The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

<h3>What is an element of a valid contract?</h3>

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

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1 year ago

A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb

densk [106]

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2 years ago

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Andru [333]

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Explanation:

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3 years ago

Conductors of large instrumental ensembles use thin stick called a __________ to help performers keep time.

Dmitry [639]

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3 years ago

Read 2 more answers

Learning Goal: To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following gene

kaheart [24]

Answer:

so the transverse displacement is 0.089963 m

Explanation:

Given data

equation y(x,t)=Acos(kx−ωt)

speed v = 9.00 m/s

amplitude A = 9.00 × 10^−2 m

wavelength λ = 0.480 m

to find out

the transverse displacement

solution

we know

v = angular frequency / wave number

and

wave number = 2 $\pi$ / λ = 2 $\pi$ / 0.480 = 13.0899 $m^{-2}$

angular frequency = v k

angular frequency = 9.00 × 13.0899

angular frequency = 117.8097 rad/sec = 118 rad/sec

equation y(x,t)=Acos(kx−ωt)

y(x,t)=9.00 × 10^−2 cos(13.0899 x−118t)

when x =0 and and t = 0

maximum y(x,t)= 9.00 × 10^−2 cos(13.0899 (0) − 118 (0))

maximum y(x,t)= 9.00 × 10^−2 m

and when x = x = 1.59 m and t = 0.150 s

y(x,t)=9.00 × 10^−2 cos(13.0899 (1.59) −118(0.150) )

y(x,t)=9.00 × 10^−2 × (0.99959)

y(x,t) = 0.089963 m

so the transverse displacement is 0.089963 m

5 0

3 years ago