175km per hour
That’s the speed it was going.
Answer:
The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"
answers:
a.
b.
Explanation:
First let state the mathematical expression for the tangential acceleration and the radial acceleration.
a. tangential acceleration is express as
since the distance is expressed as
the derivative is the velocity, hence
hence when we take the drivative of the velocity we arrive at
b. the expression for the radial acceleration is expressed as
We can use Newton's second law to find out. This says F=ma, where m is the mass we seek:
So we see the mass is 3kg
M = 45.0 g in Kg 0.045 Kg
speed = 75.0 m/sec
Δp = m * speed
Δp = 0.045* 75.0
Δp = 3.375 kg.m/s
hope this helps!
Refer to the diagram shown below.
The vertical distance traveled is
s = 25 m
The initial vertical launch velocity is zero.
Therefore
s = (1/2)*g*t²
where g = 9.8 m/s²
t = the time of flight, s
That is,
0.5*9.8*t² = 25
t² = 25/4.9 = 5.102
t = 2.26 s
Answer: 2.26 s