(a) The momentum of the proton is determined as 5.17 x 10⁻¹⁸ kgm/s.
(b) The speed of the proton is determined as 3.1 x 10⁹ m/s.
<h3>
Momentum of the proton</h3>
The momentum of the proton is calculated as follows;
K.E = ¹/₂mv²
where;
- m is mass of proton = 1.67 x 10⁻²⁷ kg
- v is speed of the proton = ?
<h3>Speed of the proton</h3>
v² = 2K.E/m
v² = (2 x 50 x 10⁹ x 1.602 x 10⁻¹⁹ J)/(1.67 x 10⁻²⁷)
v² = 9.6 x 10¹⁸
v = 3.1 x 10⁹ m/s
<h3>Momentum of the proton</h3>
P = mv = (1.67 x10⁻²⁷ x 3.1 x 10⁹) = 5.17 x 10⁻¹⁸ kgm/s
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Answer:
A. 33.77 m/s
B. 6.20 s
Explanation:
Frame of reference:
Gravity g=-9.8 m/s^2; Initial position (roof) y=0; Final Position street y= -21 m
Initial velocity upwards v= 27 m/s
Part A. Using kinematics expression for velocities and distance:

Part B. Using Kinematics expression for distance, time and initial velocity

Since it is a second order equation for time, we solved it with a calculator. We pick the positive solution.
Answer:
The correct option is;
C. 1 mile clear of clouds
Explanation:
Given that the indicated airspace location is at or below 700 feet AGL therefore, it is taken as being in the region of a class G airspace which covers the airspace regions from the base up to and equal to 1,200 feet beneath the class E airspace and the requirement for VFR flight for class G are 1 mile and clear of clouds.
The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.
The given parameters;
- magnitude of force on the object, F = 10 N
- angle between the object and the horizontal flat surface = 0⁰
Apply Newton's second law of motion to determine the magnitude of the force on the object.
Due to the position of the object, the magnitude of the force acting on it is calculated as;

Therefore, the magnitude of the force acting on the object is 10 N.
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