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Dafna11 [192]
3 years ago
5

Apparent magnitude depends mainly upon _________. our sun has a large apparent magnitude.

Physics
1 answer:
Ksenya-84 [330]3 years ago
7 0
Apparent magnitude depends mainly on the brightness of the object as seen from an observer on Earth. This is taken into account without the effects of the atmosphere.
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According to the condensation theory, the most important factor for the formation of our planets was _____. the gravitational pu
mart [117]

According to the condensation theory, the most important factor for the formation of our planets was "the interstellar dust attracting heat away from the protosun".


Condensation is the procedure by which water particles noticeable all around bunch together and shape fluid water. This is regularly observed outwardly of cold glasses. This idea additionally identifies with the solar system.

The condensation theory of the solar system expresses that our solar system, and perhaps all other galaxies, were shaped from a cloud of residue and gas that consolidated into strong issue. Space experts trust that the littlest grains of residue in our cloud applied a draw on the gas about it, 'consolidating' into bigger and bigger bits of issue, similarly as a snowball moving downhill will become bigger and bigger. In the long run, the gravitational draw of these residue atoms was sufficiently solid that they started to pull in each other, developing into greater and greater clusters that had more grounded gravitational pulls. In the long run, these bunches of residue and gas from the cloud frame a star, and potentially planets, space rocks, and comets turning about the star.

5 0
3 years ago
Read 2 more answers
The most abundant element in earth's continental crust (by weight) is____?
sashaice [31]
The answer is A. Oxygen
8 0
3 years ago
Read 2 more answers
Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

where \lambda is the wavelength of light, d is the slit width, and \theta is the diffraction angle.

From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

7 0
3 years ago
The innermost satellite of jupiter orbits the planet with a radius of 422 × 103 km and a period of 1.77 days. what is the mass o
FinnZ [79.3K]

The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.

<h3>What is the mass of Jupitar?</h3>

There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.

Given that;

T^2 = GMr^3/4π

T = period

G = gravitational constant

r = radius

M = mass of Jupitar

Now;

1 day = 86400 seconds

1.77 days = 1.77 days *  86400 seconds/1 day

= 152928 seconds

Making M the subject of the formula;

M =4πT^2/Gr^3

M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3

M = 2.9 * 10^11/5.0 * 10^24

M = 5.8 * 10^-14 Kg

Learn more about mass of a planet:brainly.com/question/13851553

#SPJ1

5 0
2 years ago
A ball is dropped from rest at the top of a 6.10 m
natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

\frac{v_1}{v} = e ( coefficient of restitution ) = \frac{1}{\sqrt{10} }

and

\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

e = \sqrt{\frac{h_1}{6.1} }

e = \sqrt{\frac{h_2}{h_1} }

So on

e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }

(\frac{1}{\sqrt{10} })^n=\frac{2.38}{6.1}= .00396

Taking log on both sides

- n / 2 = log .00396

n / 2 = 2.4

n = 5 approx

3 0
3 years ago
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