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Furkat [3]
4 years ago
9

A microwave oven operating at 120 volts is used to heat a sandwich if the oven draws 12.5 amperes of current for 45 seconds what

is the power dissipated by the oven?
Physics
1 answer:
asambeis [7]4 years ago
3 0
We can solve for the power dissipated by the oven on the given values of voltage which is 120 volts and current which is equal to 12.5 amperes.
The formula for Power dissipated is P=V*I where "v" for the voltage and "i" for the current.
P=120*12.5
P=1500 watts
The answer is 1500 watts.
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Starting from rest, a small block of mass m slides frictionlessly down a circular wedge of mass M and radius R which is placed o
guapka [62]

Answer:

Part a)

V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}

v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

y_{cm} = \frac{mR}{m + M}

Explanation:

PART A)

As we know that there is no external force on the system of two masses in horizontal direction

So here the two masses will have its momentum conserved in horizontal direction

So we have

mv + MV = 0

Also we know that here no friction force on the system so total energy will always remains conserved

So we have

\frac{1}{2}mv^2 + \frac{1}{2}MV^2 = mgR

now we have

\frac{1}{2}m(\frac{MV}{m})^2 + \frac{1}{2}MV^2 = mgR

\frac{1}{2}MV^2(\frac{M}{m} + 1) = mgR

so we have

V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}

and another block has speed

v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

y_{cm} = \frac{mR}{m + M}

7 0
3 years ago
A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie
Olin [163]

Answer:

The maximum torque is  \tau_{max} =  1.139 *10^{-7} \ N \cdot m

Explanation:

From the question we are told that

   The length of the wire is  l =  26.0 \ cm  =  0.26 \  m

     The current flowing through the wire is  I  = 5.77mA  =  5.77 *10^{-3} \ A

      The magnetic field is  B = 3.67 \ mT  =  3.67 *10^{-3 } T

         

The maximum torque is mathematically evaluated as

        \tau_{max} =   \mu B  

Where \mu  is the magnetic dipole moment which is mathematically represented as

        \mu  =  \frac{I l^2}{4 \pi n }

Where n is the number of turns which from the question is  1

    substituting values

       \mu  =  \frac{ 5.77 *10^{-3}  *  0.26^2}{4  * 3.142* 1 }

     \mu  =  3.10 4*  10^{-5}  A m^2

Now  

      \tau_{max} =  3.104 *10^{-5} * 3.67 *10^{-3}  

      \tau_{max} =  1.139 *10^{-7} \ N \cdot m  

7 0
3 years ago
A hot air balloon is moving at a speed of 10 meters/second in the +x direction. The balloonist throws a brass ball with a veloci
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A large convex lens stands on the floor. The lens is 180 cm tall, so the principal axis is 90 cm above the floor. A student hold
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B. 60 cm 

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Hope this helps !
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People build a dam to create a reservoir that supplies water a nearby city needs. Describe two ways this action will likely affe
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Due to damming the water it will not flow as fast and since it wont flow as fast it will cause the water level to rise.
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