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Furkat [3]
3 years ago
9

A microwave oven operating at 120 volts is used to heat a sandwich if the oven draws 12.5 amperes of current for 45 seconds what

is the power dissipated by the oven?
Physics
1 answer:
asambeis [7]3 years ago
3 0
We can solve for the power dissipated by the oven on the given values of voltage which is 120 volts and current which is equal to 12.5 amperes.
The formula for Power dissipated is P=V*I where "v" for the voltage and "i" for the current.
P=120*12.5
P=1500 watts
The answer is 1500 watts.
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Svet_ta [14]

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Explanation:

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3 years ago
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A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated
Lelu [443]

Incomplete question as we have not told to find what quantity.The complete question is here

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 5.00 cm.calculate: (a) the capacitance; (b) the radius of the inner sphere; (c) the electric field just outside the surface of the inner sphere.

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For part (b)

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C=\frac{4\pi e}{\frac{1}{r_{a} }-\frac{1}{r_{b} } }\\ So\\{\frac{1}{r_{a} }-\frac{1}{r_{b} } }=\frac{4\pi *8.85*10^{-12} }{1.666*10^{-11}}=6.672m^{-1} \\ \frac{1}{r_{a} }=6.672+(1 /0.05)\\\frac{1}{r_{a} }=26.672\\r_{a} =1/26.672\\r_{a} =0.0375m\\r_{a} =3.749cm

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The electric field according to Gauss Law is given by:

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7 0
3 years ago
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