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2 years ago

In the video "Shoot with great form" Klay says you should rest the ball on

Physics

1 answer:

goldfiish [28.3K]2 years ago

3 0

Palm of your hand should be the correct answer if i remember correctly

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Does anyone know the answer to this?

sweet-ann [11.9K]

Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*

3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.

Please note that y:x relations are always straight lines while relations are parabolic lines.

Hope this helps!

5 0

2 years ago

Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The

IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

$F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}$

Here,

$\mu_0$ = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

$L = 0.67m$

$m = 0.082kg$

$d = 7.4*10^{-3}m$

$I = \text{Current through each of the wires}$

Rearranging the previous equation to find the current,

$\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})$

$I = \sqrt{\frac{mgd}{(2*10^{-7})L}}$

$I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}$

$I = \sqrt{44377.9}$

$I = 210.66A$

Therefore the current in the rods is 210.6A

8 0

2 years ago

Read 2 more answers

The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter

Simora [160]

you haven't attached the diagram, but i assume that this diagram is what you were talking about

Answer:

near Y

Explanation:

the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.

5 0

2 years ago

Why do stars have names

zmey [24]

Astronomers give stars names so that they're able to identify and keep track of them more easily.

7 0

3 years ago

A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from

svlad2 [7]

Answer:

) the uniform disk has a lower moment of inertia and arrives first.

Explanation:

(a) the uniform disk has a lower moment of inertia and arrives first.

(b) Let's say the disk has mass m and radius r, and

the hoop has mass M and radius R.

disk: initial E = PE = mgh

I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh

m cancels, leaving v² = 4gh / 3

hoop: initial E = Mgh

I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh

M cancels, leaving V² = gh

Vdisk = √(4gh/3) > Vhoop = √(gh)

3 0

2 years ago