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telo118 [61]
3 years ago
7

Diffraction spreading for a flashlight is insignificant compared with other limitations in its optics, such as spherical aberrat

ions in its mirror. To show this, calculate the minimum angular spreading in rad of a flashlight beam that is originally 5.90 cm in diameter with an average wavelength of 610 nm.
Physics
1 answer:
deff fn [24]3 years ago
8 0

Answer:

The answer is "1.2566 \times 10^{-5}\,rad".

Explanation:

As per the Rayleigh Criterion the minimum angular spreading, for a circular aperture:

\theta_{\mathrm{min}}\approx \sin\theta=1.22\,\frac{\lambda}{d}  

\theta_{\mathrm{min}}=\mathrm{1.22\,\frac{\left( 610\,nm \right)}{\left( 5.90\,cm \right)}=1.22\,\frac{\left( 610\times10^{-9}\,m \right)}{\left( 5.90\times10^{-2}\,m \right)}}

                               =1.22\times 103.389 \times 10^{-7}\\\\=1.22\times 1.03 \times 10^{-5}\\\\=\mathrm{1.2566 \times 10^{-5}\,rad}

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Answer:

C. Talk test

Explanation:

The talk test would be readily available to me at the the least cost.

The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.

The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.

7 0
3 years ago
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Explain how wavelength and frequency are important in determining the type of light.
asambeis [7]
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7 0
3 years ago
Dos cargas puntuales (q1 y q2 ) se atraen inicialmente entre sí con una fuerza de 550 N , si la separación entre ellas es de 90
antiseptic1488 [7]

Answer:

q2 = 9.02*10^{-4}C

Explanation:

To find the value of the other charge you use the Coulomb's law:

F=k\frac{q_1q_2}{r^2}

k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2

q1: charge 1 = 55*10^{-6}C

r: distance between charges = 90cm = 0.9m

F: electric force = 550N

By doing q2 the subject of the formula and replacing you obtain:

q_2=\frac{r^2F}{kq_1}=\frac{(0.9m)^2(550N)}{(8.98*10^9Nm^2/C^2)(55*10^{-6}C)}=9.02*10^{-4}C

hence, the value of the other charge q2 is 9.02*10^{-4}C

6 0
3 years ago
All moving objects have ____________.<br> A. Force<br> B. Distance<br> C. Momentum<br> D. Time
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Answer:

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Explanation:

Mark as brainliest if it is right

5 0
2 years ago
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Two 1.0 g balls are connected by a 2.0-cm-long insulating rod of negligible mass. One ball has a charge of +10 nC, the other a 4
Irina18 [472]

Answer:

  α = 5 10⁻³ rad / s²

Explanation:

For this exercise we can use Newton's second law for rotational movement, where the force is electric

             τ = I α

Where the torque is

             τ = F x r = F r sin θ

Strength is

              F = q E

The moment of inertia of a small ball, which we approximate to a point is

             I = m r²

We replace

            2 (q E) r sin θ   = 2m r² α

The number 2 is because the two forces create the same torque

             α = q E sin θ / m r

Let's reduce the magnitudes to the SI system

           m = 1.0g = 1.0 10⁻³ kg

           L = 2.0 cm = 2.0 10⁻² m

           q = 10 nc = 10 10⁻⁹ C

           E = 1.0 10 N / C

           r = L / 2

           r = 1.0 10⁻² m

Let's calculate

           α = 10 10⁻⁹ 1.0 10 sin 30 / 1.0 10⁻³ 1.0 10⁻²

           α = 5 10⁻³ rad / s²

5 0
3 years ago
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