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Troyanec [42]
3 years ago
11

A particular reactant decomposes with a half-life of 113 s when its initial concentration is 0.372 M. The same reactant decompos

es with a half-life of 223 s when its initial concentration is 0.189 M. Calculate the rate constant (k) and reaction order?
Chemistry
1 answer:
AysviL [449]3 years ago
8 0

Answer:

Rate constant =  0.0237 M-1 s-1, Order = Second order

Explanation:

In this problem, it can be observed that as the concentration decreases, the half life increases. This means the concentration of the reactant is inversely proportional to the half life.

The order of reaction that exhibit this relationship is the second order of reaction.

In the second order of reaction, the relationship between rate constant and half life is given as;

t1/2 = 1 / k[A]o

Where;

k = rate constant

[A]o = Initial concentration

k = 1 / t1/2 [A]

Uisng the following values;

k = ?

t1/2 = 113

[A]o = 0.372M

k = 1 / (113)(0.372)

k = 1 / 42.036 = 0.0237 M-1 s-1

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First, we need to calculate the principal quantum number n for this electron, using the equation:
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