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3 years ago

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Chemistry

1 answer:

Rom4ik [11]3 years ago

5 0

Answer:

6. 355.1 g of Na₂SO₄ can be formed.

7. 313 g of LiNO₃ were needed

Explanation:

<u>Excersise 6</u>.

The reaction is: 2 NaOH + H₂SO₄ --> 2 H₂O + Na₂SO₄

2 moles of sodium hydroxide react with 1 mol of sulfuric acid to produce 2 moles of water and 1 mol of sodium sulfate.

If we were noticed that the acid is in excess, we assume the NaOH as the limiting reactant. Let's convert the mass to moles (mass / molar mass)

200 g / 40 g/mol = 5 moles.

Now we apply a rule of three with the ratio in the reaction, 2:1

2 moles of NaOH produce 1 mol of sodium sulfate.

5 moles of NaOH would produce (5 .1)/2 = 2.5 moles

Let's convert these moles to mass (mol . molar mass)

2.5 mol . 142.06 g/mol = 355.1 g

<u>Excersise 7.</u>

The reaction is:

Pb(SO₄)₂+ 4 LiNO₃ → Pb(NO₃)₄ + 2Li₂SO₄

As we assume that we have an adequate amount of lead (IV) sulfate, the limiting reactant is the lithium nitrate.

Let's convert the mass to moles (mass / molar mass)

250 g / 109.94 g/mol = 2.27 moles

Let's make a rule of three. Ratio is 2:4.

2 moles of lithium sulfate were produced by 4 moles of lithium nitrate

2.27 moles of Li₂SO₄ would have been produced by ( 2.27 .4) / 2 = 4.54 moles.

Let's convert these moles to mass (mol . molar mass)

4.54 mol . 68.94 g/mol = 313 g

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How many grams of fluorine are contained in 8 molecules of boron trifluoride?

Lelu [443]

<h3>Answer:</h3>

7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

Number of Molecules = 8

M.Mass of BF₃ = 67.82 g.mol⁻¹

Mass of Fluorine atoms = ?

Step 1: Calculate Moles of BF₃

Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

Moles = 8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Moles = 1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

Moles = Mass ÷ M.Mass

Solving for Mass,

Mass = Moles × M.Mass

Putting values,

Mass = 1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

Mass = 9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

67.82 g BF₃ contains = 57 g of F

So,

9.0 × 10⁻²² g will contain = X g of F

Solving for X,

X = (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

X = 7.57 × 10⁻²² g of F

4 0

4 years ago

Read 2 more answers

Que es la lluvia acida?

givi [52]

Answer:

sour

Explanation:

8 0

3 years ago

What's the balanced equation for cellular respiration?

Alik [6]

<span>Correct answer is:

$C_{6}H_{12}O_6+6O_{2}\Rightarrow 6CO_{2}+6H_{2}O+energy$

But how to get there?

Let's start with simple explanation of what exactly is cellular respiration.

Cellular respiration is a multistage biochemical oxidation process of organic substances when prime product is energy (ATP - adenosine triphosphate) and other are released waste products. Cellular respiration takes place even if other metabolic processes are stopped, but cellular respiration may differ in particular organism groups.Some reactions during whole process of cellular respiration are similar in all types of living organisms.

Cellular respiration is prime indication of declining living processes.Only viruses which are on the edge of living organism and chemical particle are not performing cellular respiration.But to the point :P

In cellular respiration all substrates which are in the cell might be organic, but mostly we are using sugar oxidation - glucose in the presence of oxygen. Chemical formula of sugar looks like this:

$C_{6}H_{12}O_6$

Oxygen is just

$O_2$

so for now we have just part of the equation:

$C_{6}H_{12}O_6+O_{2}\Rightarrow$

But what would be on the right hand side?

It's quite simple, remember equation of full combustion? If we want to burn something we need oxygen like in the equation, so the product of this equation would be carbon dioxide, water and of course energy (ATP).Carbon dioxide formula looks like this:

$CO_{2}$

As a reminder water formula:

$H_{2}O$

Full formula would look like that:

$C_{6}H_{12}O_6+O_{2}\Rightarrow\ CO_{2}+H_{2}O+energy$

But still as you see this equation is unbalanced, after balancing it would like that:

$C_{6}H_{12}O_6+6O_{2}\Rightarrow 6CO_{2}+6H_{2}O+energy$

At the end I would like to explain one more thing. Energy which has been released during this process is part of high-energy connection which might be used to perform chemical reactions in the cell or to move organism for example in muscles. We need to remember that production of ATP is not happening with 100% efficiency and part of this energy is released as heat.</span>

5 0

3 years ago

In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account

hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0

3 years ago

Water is a pure substance. Which of the following is true about water? (4 points) Its compounds can only be physically separated

jonny [76]

Answer:

Water/H20 is a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.

Explanation:

7 0

3 years ago