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aleksandrvk [35]
3 years ago
7

An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?

Chemistry
1 answer:
matrenka [14]3 years ago
6 0

Answer:

In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.

Explanation:

C1×N1 = C2×N2

If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.

Balancing the two,

3 × A = -2 × B

To be equal, A = 2 and B = 3

Therefore, A²B³

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Which would least strongly attract electrons from other atoms in a compound?
sergey [27]
The concept we are looking for here is electronegativity. This concept is a measure of how strong an atom or element can attract a pair, that is bonding, of electrons to itself. 

Fluorine is the element or atom of the greatest electronegativity. Electronegativity would increase as we move left to right of the periodic table. 

 
4 0
3 years ago
Chlorobenzene, C6H5Cl, is used in the production of many important chemicals, such as aspirin, dyes, and disinfectants. One indu
trapecia [35]
3.8 mole Cl2
Explanation:
3.8molesC6H5Cl x 1moleCl2/ 1mole C6H5Cl
7 0
3 years ago
During a storm, a tree fell over into a river. What might happen to this tree?
mina [271]
Break down in to tiny prices as the water hit the tree
6 0
3 years ago
As salinity increases:
Mashcka [7]

Answer: Option (d) is the correct answer.

Explanation:

The amount of salt present or dissolved in water or water body is known as salinity.

When salinity increases then number of particles increases, therefore, density will increase. Also, number of ions will decrease thus, electrical conductivity will decrease.

On the other hand, increase in salinity will increase the amount of salt (NaCl) is the water.

Thus, we can conclude that out of the given options, the option all of the above is true.

8 0
3 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
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