Question

The number 45,28, and 53 form a Pythagorean triple

Answer 1

To be a Pythagorean triple, the numbers must satisfy the Pythagorean theorem:

$a^2+b^2=c^2$

so check:

$45^2+28^2=53^2\\\\2025+784=2809$

and that holds, so the statement is TRUE