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Anna [14]
3 years ago
11

Question 16

Physics
1 answer:
julsineya [31]3 years ago
3 0
More mass is the correct answer.
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A 15-N force and a 45-N force act on an object in opposite directions
lidiya [134]

Answer:

30-N

Explanation:

Because they are both acting on an object going opposite directions, then you simply subtract the 15 from 45 as 45N of force is stronger than 15N of force.

8 0
3 years ago
Two iron rods are placed horizontally, touching end-to-end. One end of one rod is heated. After some time, the other rod also fe
algol13
The answer is D) <span>The molecular movement in the first rod transferred energy to the molecules in the second.</span>
6 0
4 years ago
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You exert 20 newtons of force on the hammer to remove the nail. The hammer exerts 90
andrezito [222]

Answer:

20 n

Explanation:

7 0
3 years ago
a wheel 0.35m in diameter rotates at 2200rpm. calculate its angular velocity in rad/s and its linear speed and acceleration of a
bazaltina [42]

Answer:

( Angular Velocity = ( About ) 230 rad / s,

( Linear Speed = ( About ) 40.25 m / s,

( Acceleration = ( About ) 9290 m / s^2

Explanation:

Here we want the angular velocity in radians per second, the linear velocity and acceleration.

The diameter = .35 meters, and thus we can conclude that the radius be half of that, or .175 meters. For part ( a ), or the calculation of the angular velocity, it is given that the diameter rotates at 2200 revolutions per minute - but we need to convert this into radians per second.

We can say that there are 2π radians for every minute, and for every minute there are 60 seconds. Therefore -

( a ) w = 2,200 rpm( 2π rads / rev )( 1 min / 60 sec )...

Hence, w = ( About ) 230 rad / s

_____

For this second part we can calculate the the linear velocity by multiplying the angular velocity ( omega ) by the radius r -

( b ) v = w( r ) - Substitute,

v = ( 230 rad / sec )( .175 m )...

v = ( About ) 40.25 m / s

_____

And for this last bit here, to find the acceleration we can simply take the angular velocity ( omega ) squared, by the radius r -

( c ) a_{rad} = w^2( r ),

a_{rad} = ( ( 230 rad / sec )^2 )( .175 m )...

a_{rad} = ( About ) 9290 m / s^2

7 0
3 years ago
Suppose a large truck on a hydraulic lift exerts 7,000 N of force on a piston with an area of 0.4 m2. The piston can only suppor
uysha [10]

Pressure is the amount of force per unit area. In formula it is,

P = F ÷ A

P = 7000 N ÷ 0.4 m2

P = 17,500 N/m2

The amount of pressure the truck exerts on the piston is 17,500 N/m2

7 0
3 years ago
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