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2 years ago

The

Physics

1 answer:

yKpoI14uk [10]2 years ago

5 0

13.6g

136g

Explanation:

Given parameters:

Density of mercury = 13.6g/cm³

Unknown:

Mass of :

1cm³ of mercury

10cm³ of mercury

Solution:

Density is the mass per unit volume of a substance. It is the amount of matter in a given volume.

Density = $\frac{mass}{volume}$

Since the unknown in the problem is mass;

Mass = density x volume

Mass of 1cm³ of mercury = 13.6 x 1 = 13.6g

Mass of 10cm³ of mercury = 10 x 13.6 = 136g

learn more:

Density problems brainly.com/question/3433940

#learnwithBrainly

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ELEN [110]

Answer:

20m

Explanation:

P.E=mgh

2000=10×10×h

2000=100h

Divide both side by 100

2000/100=20

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2 years ago

The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part t

UNO [17]

Answer:

$\alpha=-3.01dB$

Explanation:

From the question we are told that:

Sound level intensity

$\triangle I=40dB-80dB$

Generally the equation for intensity level is mathematically given by

$\alpha=10log_{10}(I/I_x)dB$

Where

I= Intensity measured

$I_x=Threshold\ of\ audibility$

$I_x= 10-12 W / m2$

$\alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}$

$\alpha= 10 log10 \frac{I_1}{I_2}$

$\alpha=10 log10\frac{40}{80}$

$\alpha=-3.01dB$

7 0

2 years ago

In the flow past a compression corner, the upstream Mach number and pressure are 3.5 and 1 atm, respectively. Downstream of the

yulyashka [42]

Answer:

$\theta=23.7^{\circ}$

Explanation:

The ratio of pressure 2 to 1 us 5.48/1= 5.48 rounded off as 5.5.

Referring to table A.2 of modern compressible flow then $M_{\beta_1}=2.2$

Also

$M_{\beta_1}=M_1 sin \beta$ and making $sin\beta$ the subject of the formula then

$sin\beta=\frac {2.2}{3.5}\\\beta=38.94^{\circ}$

Making reference to $\theta-\beta-M$ diagram then

$\theta=23.7^{\circ}$

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2 years ago

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

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2 years ago

Which scientist is often called the “father of the atomic bomb” because of his work as the head of the manhattan project?

kirza4 [7]

Answer:

J. Robert Oppenheimer

Explanation:

He led the Manhattan project and created the first nuclear bomb in WWII

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3 years ago