Answer:
This unknown compound has a molar mass of 33.74g/mole
Explanation:
<u>Step 1:</u> Given data
The formula for the osmotic pressure is:
π = MRT = 14.5 atm
⇒ with M = Concentration of the solution
⇒ with R = gas constant = 0.08206 L atm / mol K
⇒ with T = absolute temperature (in Kelvin) = 298K
<u>Step 2:</u> Calculate concentration
M = π/ RT
M = 14.5 / (0.08206 * 298)
M = 0.593 M this is 0.593 moles per L
<u>Step 3:</u> Calculate number of moles
Since the volume is only 0.250 L, the amount of moles is:
0.593 * 0.250 L = 0.1482 moles
<u>Step 4:</u> Calculate molar mass
The molar mass is : mass / moles
Molar mass of this unknown compund = 5g / 0.1482 moles = 33.74 g/mole
This unknown compound has a molar mass of 33.74g/ mole
Answer: Parts per million (ppm)
Explanation:
Consider the units milligram per milliliter. This gives us one part of the solute per one million parts of solvent. That is 10^ -3/10^-3= 10^-6. This unit is commonly used in analytical chemistry to show very small concentration of analyte. A similar unit is parts per billion(ppb)
Answer : The specify the l and ml values for n = 4 are:
At l = 0, 
At l = 1, 
At l = 2, 
At l = 3, 
Explanation:
There are 4 quantum numbers :
Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....
Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from
. When l = 2, the value of
will be -2, -1, 0, +1, +2.
Spin Quantum number : It describes the direction of electron spin. This is represented as
The value of this is
for upward spin and
for downward spin.
As we are given, n = 4 then the value of l and ml are,
l = 0, 1, 2, 3
At l = 0, 
At l = 1, 
At l = 2, 
At l = 3, 
<u>Answer:</u> The molarity of the stock solution is 4.64 M
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:

Hence, the molarity of the stock solution is 4.64 M
Answer:
The value is 
Explanation:
From the question we are told that
The bond length is
The bond dipole moment is 
Generally the dipole moment is mathematically represented as

Here Q is the partial negative charge on the bromine atom
So

=> 
=> 
Generally
1 electronic charge(e) is equivalent to 
So x electronic charge(e) is equivalent to 
=> 
=> 