The percentage of Chromium in Chromium Oxide is calculated as follow,
Step 1: Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u
Step 2: Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
=
![\frac{103.98}{151.98}](https://tex.z-dn.net/?f=%20%5Cfrac%7B103.98%7D%7B151.98%7D%20)
× 100
=
68.41 %
So, the %age composition of chromium in chromium oxide is
68.41 %.
Answer:
Project scope statement?
Explanation:
it's good one just do research on it
6840 is the answer hope this help
Answer:
Well, electrons can be converted into a atomic number so if SE atomic number is 34 that means it has 34 electrons. AI has a atomic number of 13 meaning it has 13 electrons. So the difference is that SE has more electrons then AI.
Answer:
length of wire = 38.82 m
Explanation:
∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm
∴ m spool = 1 Lb = 453.592 g
∴ ρ = 8.92 g/cm³
cross section area:
⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²
⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )
⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m