All categories

3 years ago

For the percent 82%, (a) write a decimal and (b) write a fraction in lowest terms.

Mathematics

2 answers:

Tasya [4]3 years ago

5 0

Answer:

a) .82, b) 41/50

Step-by-step explanation:

a) The decimal form would be 0.82 - when writing a percentage as a decimal, we use 0.0-1.0 to represent 0% through 100%. Since it is 82%, it would translate to .82!

b) Since it is 82% out of 100%, we would write the fraction as 82/100. Additionally, you can divide it by 2 to get 41/50, thus reaching its simplest form!

ale4655 [162]3 years ago

3 0

Answer:

.82

41/50

Step-by-step explanation:

82%

Move the decimal 2 places to the left to change to decimal form

.82

Percent means out of 100

82/100

Divide by 2

41/50

You might be interested in

Factor each expression 45c+ 10d

GarryVolchara [31]

Since you can factor 5 out of both 45c and 10d, the expression will be 5(9c+2d)
5(9c+2d)
=)=)=)

6 0

2 years ago

mary spends 40% of her monthly earnings on rent and 10% of the remaining amount on entertainment. If she spends $800 for rent, h

liraira [26]

Answer:

Step-by-step explanation:

40% of the earnings is spent on rent.

The earnings is an unknown, so we call it x.

The rent is $800, so 40% of x equals $800.

40% * x = 800

0.4x = 800

x = 800/0.4

x = 2000

She earns $2000 per month.

After paying rent, the remaining amount is

$2000 - $800 = $1200

She spends 10% of the remaining amount on entertainment.

10% of $1200 = 10% * $1200 = 0.1 * $1200 = $120

5 0

3 years ago

Please help me <br><br> dont take my points

oksian1 [2.3K]

1. √16 = 4
2. √2.25 = 1.5
3. 6^2 / 9 *2 = 8
4. 12-2 / 6+4 = 1
5. √16+9 = 5
6. 63 / 3^2 + |2| = 9

3 0

2 years ago

Read 2 more answers

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

(Picture up top) Lines XU and WY intersect at point A. Based on the diagram, determine if the statement is True or False t.

Leokris [45]

Answer: The answer would be B. False. (Please give me a thanks it'll help out a lot.)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers