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dimulka [17.4K]
3 years ago
13

The number of electrons in outer ring for cesium

Chemistry
1 answer:
Degger [83]3 years ago
5 0
The number of electrons in outer ring for cesium would be ONE 1.
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0:00 一<br> what is 18,000 divided by 450,000 in scientific notation
ankoles [38]

Answer:

4 × 10-2

(scientific notation)

= 4e-2

(scientific e notation)

= 40 × 10-3

(engineering notation)

(thousandth; prefix milli- (m))

Explanation:

All of the anwsers

3 0
3 years ago
Why does Australia get more UV light than the other parts of the world?
Nataly [62]
During summer, the Earth's orbit brings Australia closer to the sun (as compared to Europe during its summer), resulting in an additional 7% solar UV intensity. Coupled with our clearer atmospheric conditions, this means that Australians are exposed to up to 15% more UV than Europeans.
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3 years ago
A colligative property is when the addition of a solute to a solvent alters the boiling point or The freezing point of a solvent
Mrrafil [7]

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4 0
3 years ago
How waves affect matter at the macroscopic and particle levels?
solmaris [256]
Reflection, refraction, and diffraction

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5 0
3 years ago
A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p
Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL

Putting values in above equation, we get:

3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0
3 years ago
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