The number of electrons in outer ring for cesium

Clo3− draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show t

Karo-lina-s [1.5K]

The formal charges of all nonhydrogen atoms are -1.

Solution:-

O 7-4 = 3 O Double bond on one H 5-4 = 1

O-Cl-O 6-7 = -1x4 = -4 N 5-4=1 H-N-H 1-1=0

O 3-4= -1 O O 6-7 = -1(2)=-2 H 1-0=+1

6-6 = 0 1-2 = -1

It will percentage its last valence electron thru a single bond to the terminal oxygen atom. This is in agreement with carbon and hydrogen atoms that each need to form 4 and 1 covalent bonds respectively. because the terminal oxygen atom best has a single covalent bond, it'll have a proper rate of -1.

According to the lewis structure of SO2, The critical atom is sulfur and it is bonded with 2 oxygen atoms thru a double bond. each oxygen atom acquires 2 lone pairs of electrons and the primary sulfur atom has 1 lone pair of electrons.

Learn more about Nonhydrogen atoms here:-brainly.com/question/2822744

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3 0

1 year ago

5. _______H2O2 → ________ H2O + O2

Naddika [18.5K]

Answer:

Hope this helps! （；＿；)/

Explanation:

3 0

2 years ago

How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?

vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0

3 years ago

A precipitate is a solid that sometimes forms when two liquids combine. A true B False

r-ruslan [8.4K]

<h2>Question:</h2>

A precipitate is a solid that sometimes forms when two liquids combine.

<h2>Answer:</h2>

A. True 

<h2>Explanation:</h2>

Because the Precipitate it's forms solid when two liquids combine to precipitate.

<h2>#CARRYONLEARNING </h2><h2>#STUDYWELL </h2>

3 0

3 years ago

Read 2 more answers

Which of the following statements is true?

VikaD [51]

The answer is likely to be A

7 0

3 years ago

Read 2 more answers