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Len [333]
3 years ago
9

A person's prescription for bifocals is -0.25 diopter for distant vision and +2.50 diopters for near vision, the near vision bei

ng accomplished by inserts into the distant vision lens. What is the net power of the near vision correction?
Physics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

net power is + 2.25 D

Explanation:

Given data

distance vision = -0.25 D

near vision = + 2.50 D

to find out

net power

solution

we have given a person lens power for near is - 0.25 diopter and lens power for near power is  +2.50 diopter so

net power is sum of both the power vision

so

net power = distance + near power

put both value we get net power

net power = ( -0.25 D) + ( + 2.50 D)

net power = + 2.25 D

so net power is + 2.25 D

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potential energy

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Answer:

50m; 0m/s.

Explanation:

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V^{2} = U^{2} + 2aS

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  • V represents the final velocity measured in meter per seconds.
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<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

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3 years ago
HOLA, NECESITO AYUDA!
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The electrostatic force between the two ions is 2.9\cdot 10^{-10} N

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

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In this problem, the ion of sodium has a charge of

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while the ion of chlorine has a charge of

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Substituting, we find the electrostatic force between the two ions:

F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N

where the negative sign simply means that the force is attractive, since the two ions have opposite charge.

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