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victus00 [196]
3 years ago
10

A car is traveling at 10 m/s. 10 seconds later the car is traveling 40 m/s. What is the car’s acceleration?

Physics
1 answer:
ratelena [41]3 years ago
3 0

Answer:

a = 3 m/s^2

Explanation:

Vi = 10 m/s

Vf = 40 m/s

t = 10 s

Plug those values into the following equation:

Vf = Vi + at

40 = 10 + 10a

---> a = 3 m/s^2

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The density of solid copper is 8960 kg/m3.
Ahat [919]

Explanation:

The density of a solid copper is 8960kg/m^3 while the density of a molten copper is 7900kg/m^3 this is due to the difference in the state of matter, the solid copper is in solid state while the molten copper is in form of a liquid. In the solid copper atoms are tightly pack while they atom are not tightly packed.

3 0
3 years ago
Please i need your help w/h/w you make the following measurements if an object:42kg, and 22m​
Rufina [12.5K]

Answer:

1.9 kg/m^3

Explanation:

The density of an object is given by

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

In this problem,

m = 42 kg

V = 22 m^3

Substituting into the equation, we find the object's density:

d=\frac{42 kg}{22 m^3}=1.9 kg/m^3

8 0
3 years ago
Calculate the water pressure in the pipes at the bottom of a high-rise building that is fed by reservoir 60 m above the roof top
yan [13]
P + gh 
14 + (9.8)(60) = 602kPa
5 0
3 years ago
Work out the current through an electric heater with a power of 1.38kW if it uses the 230V mains supply.
love history [14]

Answer:

I = 6 A

Explanation:

Given that,

Power of an electric heatr, P = 1.38 kW

The voltage of the mains supply, V = 230 V

We need to find the current through the heater. The electric power in terms of  voltage and current is given by :

P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1.38\times 10^3}{230}\\\\I=6\ A

So, the current through an electric heater is 6 A.

5 0
3 years ago
Objects with masses of 181 kg and 712 kg are separated by 0.442 m. A 72.6 kg mass is placed midway between them. 0.442 m b b 181
Semmy [17]

Answer:

The Force exerted by the two objects will be same and 4,401,189.49  × 10−11 N

Explanation:

Let m1 be the mass of the first object and m2 be the mass of the second object and the distance between them be d. Then

m1= 181kg

m2= 712 kg

d= 0.442 m

G is the gravitational Constant

According to Newtons Law Gravitational Force is given by

F=G m1 m2 /d²

F= 6.672 × 10−11 ×181×712/(0.442)²

F=  859,576.24  × 10−11/0.195364

F=  4,401,189.49  × 10−11 N

The Force exerted by the two masses on the third mass will be same and 4,401,189.49  × 10−11 N

5 0
3 years ago
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