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Shkiper50 [21]
3 years ago
6

Does a resistor resist current or voltage

Physics
1 answer:
KIM [24]3 years ago
4 0
The answer is current
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Que propiedad de la Luz se produce cuando ves tu cara reflejada en la cuchara?
kramer

Answer:

refracción

Explanation:

I don't speak spanish but that's the answer

5 0
3 years ago
What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds
Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N

The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

3 0
3 years ago
How to get stud multipliers in lego star wars the skywalker saga?.
Anna11 [10]
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7 0
2 years ago
1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5
____ [38]

Answer:

1.785 m/s

Explanation:

The momentum can be calculated using the expression below

M1 *V1 + M2 * V2 = (M1+M2) V3

M1= mass of van=9000 kg

M2= mass of car= 850kg

V3= velocity of entangled car

V1= Velocity of the van= 0

V2= velocity of the car= 5 m/ s

Substitute the values

(900×0) + (500×5)=( 900+500)× V3

2500=1400 V3

V3=2500/1400

V3= 1.785 m/s

Hence, velocity of the entangled cars after collision is 1.785 m/s

8 0
2 years ago
You are working at a company that manufactures electri- cal wire. Gold is the most ductile of all metals: it can be stretched in
Alona [7]

Explanation:

We know that the relation between volume and density is as follows.

      Volume = \frac{\text{mass}}{\text{density}}

So,       V = \frac{10^{-3}}{19.3 \times 10^{3} kg/m^{3}}

               = 5.181 \times 10^{-8} m^{3}

Now, we will calculate the area as follows.

      Area = \frac{\text{volume}}{\text{length}}

               = \frac{5.181 \times 10^{-8} m^{3}}{2.4 \times 10^{3}}

               = 2.15 \times 10^{-11} m^{2}

Formula to calculate the resistance is as follows.

         R = \rho \frac{l}{A}

             = \frac{2.44 \times 10^{-8} \times 2400}{}2.15 \times 10^{-11}}

             = 2.71 \times 10^{6} ohm

Thus, we can conclude that the resistance of given wire is 2.71 \times 10^{6} ohm.

4 0
3 years ago
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