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astraxan [27]
3 years ago
15

A statue is made of bronze, which is an alloy of about 80% copper and 20% tin. Which metal is in the higher concentration in thi

s bronze statue?
A.The concentrations of each metal in the statue are equal.
B.The statue has a higher concentration of copper.
C.Tin is more concentrated in the statue.
Physics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

<h2>B. The statue has a higher concentration of copper.</h2>

Explanation:

We know by given that the statue is made of bronze, which is formed by 80% copper and 20% tin.

So, as you can observe, the copper represents a majority of the statue, that means it has more concentration of copper than tin.

Therefore, the right answer is B. The statue has a higher concentration of copper, because it's made 80% of copper actually.

skad [1K]3 years ago
3 0
The answer is B because it's 80 percent copper, that's a greater number then 20.
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Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
The units we use to measure the sound intensity level are _____.
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Answer:

decibels (dB)

Explanation:

The sound intensity level is a quantity derived from the sound intensity.

The intensity of a wave is defined as the power of the source of the wave divided by the area through which the power of the wave is spread, mathematically:

I=\frac{P}{A}

where

P is the power of the source

A=4\pi r^2 is the surface area over which the wave spreads (assuming that the wave propagates in all directions, it corresponds to the surface area of a sphere of radius r, where r is the distance between the source of the wave and the observer)

For sound waves, the intensity is often expressed using another unit, called decibel (dB), defined as follows:

\beta(dB)=10Log_{10}(\frac{I}{I_0})

where

\beta is the sound intensity level in decibels

I is the intensity of the sound wave

I_0=1\cdot 10^{-12} W/m^2 is the threshold intensity of a sound that a person can normally hear.

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goblinko [34]

From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.

We make use of the following formula

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Where

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Make F' the subject of the equation

F' = mv²/2d.................. Equation 2

From the question,

Given:

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Substitute these values into equation 2

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Hence, The average stopping force acting on the arrow is 90 N

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ANTONII [103]

Answer:

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δ=(F*L)/(A*E)

As Force,Area and Length is same

δ∞1/E

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