To develop this problem it is necessary to apply the concepts related to the proportion of a neutron star referring to the sun and density as a function of mass and volume.
Mathematically it can be expressed as
Where
m = Mass (Neutron at this case)
V = Volume
The mass of the neutron star is 1.4times to that of the mass of the sun
The volume of a sphere is determined by the equation
Replacing at the equation we have that
Therefore the density of a neutron star is 
The wire vibrates back and forth between the poles of the magnet.
The frequency of the vibration is the frequency of the AC supply.
The amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.
<h3>What is the capacitance?</h3>
The capacitance has to do with the amount of charge that is stored by a capacitor. We know that a capacitor is a device that can be used to store electric charges. We have in it, two capacitors separated by a dielectric material.
Hence, the amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.
Learn more about capacitor:brainly.com/question/17176550
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Answer:
a. the amount of work done on a system is dependent of pathway
Explanation:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.
ΔU = Q - W
Where;
Q, the net heat transfer into the system depends on the pathway
W, the net work done by the system also depends on the pathway
But, ΔU, the change in internal energy is independent of pathway
Therefore, the correct option is "A"
a. the amount of work done on a system is dependent of pathway
Two resistors in series are often called a 'voltage divider', because the
total voltage divides in proportion to the resistances.
The total resistance in the string across the battery is (11 + 6) = 17 ohms.
-- The full battery voltage appears across 17 ohms.
-- The voltage across the 11-ohms is (11/17) of the battery, and
-- the voltage across the 6-ohms is (6/17) of the battery.
(6/17) x (B) = 9 volts
Multiply each side by (17/6) : B = (9 volts) x (17/6) =<em> 25.5 volts </em>.
By the way, in case you care or are asked . . .
-- The current in the whole series loop is B/R = 25.5 / 17 = 1.5 Amperes
-- The power drawn from the battery is B²/R = (25.5)²/17 = 38.25 watts
-- The power dissipated by the 6-ohm resistor is V²/R = 9²/6 = 13.5 watts
-- The power dissipated by the 11-ohm resistor is I²R = (1.5)² (11) = 24.75W
-- (Check: 13.5W + 24.75W = 38.25W yay! )
-- If they're just composition units hanging out in the air, then both resistors
are getting quite warm.
