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3 years ago

Physics question, any help is appreciated :)

Physics

2 answers:

Gekata [30.6K]3 years ago

8 0

Runner 2 sees Runner 1 passing him with a velocity of 17 m/s west.

Rainbow [258]3 years ago

4 0

The velocity of 17 m/s west is the answer.

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1. A stone of mass 0.8 kg is attached to a 0.9 m long string. The string will break if the tension exceeds 60 N. The stone is wh

melamori03 [73]

Answer:

1. A. 8.22. m/s

Explanation:

7 0

3 years ago

Two 90.0-kilogram people are separated by 3.00 meters. What is the magnitude of the gravitational force that one person exerts o

VARVARA [1.3K]

Answer:

the magnitude of gravitational force is 6 x 10⁻⁸ N.

Explanation:

Given;

mass of the two people, m₁ and m₂ = 90 kg

distance between them, r = 3.0 m

The magnitude of gravitational force exerted by one person on another is calculated as;

$F = \frac{Gm_1m_2}{r^2} \\\\$

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

$F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{6.67\times 10^{-11} \times \ 90 \ \times \ 90}{3^2} \\\\F = 6\times 10^{-8} \ N$

Therefore, the magnitude of gravitational force is 6 x 10⁻⁸ N.

4 0

3 years ago

while standing on the sidewalk facing the road, you see a bicyclist passing by toward your right. in the reference frame of the

cricket20 [7]

Answer:

Consider frames X and Y:

If X sees Y moving to his right then Y must see X moving to his right.

If this is not true then one can choose one frame over the other ( a favored frame and this is not allowed)

7 0

3 years ago

What percentage of all traffic deaths occur in cars traveling less than 60 mph?

Alina [70]

This is a bit too broad. Maybe this is something to google up

5 0

3 years ago

A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark

Natali5045456 [20]

The total displacement of the toy car at the given positions is 0.

The given parameters;

First displacement of the car, = 5 cm left
Second displacement of the car, = 8 cm right
Third displacement of the car, = 3 cm to the left

The total displacement of the car is calculated as follows;

Let the left direction be "negative direction"
Let the right direction be "positive direction"

$\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0$

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

6 0

2 years ago

Read 2 more answers