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fgiga [73]
4 years ago
5

______ 4. Justin was creating a chart comparing the potential energy between charged particles and the potential energy of magne

ts. Which of the following is true?
A. The potential energy between both like charges and like poles increases as they move closer together.
B. The potential energy increases between like charges and decreases between like poles as they move closer together.
C. The potential energy between both like charges and like poles decreases as they move closer together.
D. The potential energy decreases between like charges and increases between like poles as they move closer together.
Physics
1 answer:
fredd [130]4 years ago
4 0

Answer:

The correct option is;

A. The potential energy between both like charges and like poles increases as they move closer together

Explanation:

Here we have that when we move the like poles of two bar magnets close to each other, there is an increased resistance in the continuing motion, therefore for each extra gap closer achieved, there is an increase in potential energy

Similarly, when two like charges are brought closer together, the potential energy, or the energy available to push the two like charges apart increases charge as the as the charges are brought closer together

Therefore, the correct option is the potential energy between both like charges and like poles increases as they move closer together.

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Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
3 years ago
Find the temperature
mote1985 [20]

Where is the Temperature bud?

5 0
3 years ago
Read 2 more answers
A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Dete
a_sh-v [17]

Answer:

(a) 0 (b) F=1.67\times 10^9\ N

Explanation:

Given that,

Mass of a supertanker, m=1.7\times 10^8\ kg

The engine of a generate a forward thrust of, F=7.4\times 10^5\ N

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N

Hence, this is the required solution.

4 0
3 years ago
Why the watt is called derived unit ?​
Yuri [45]

Answer:

It is because it is a unit of Power(which is a derived quantity)

4 0
3 years ago
A flashlight bulb is connected to two dry cells with an equivalent voltage of 4.50 V. If the bulb draws a current of 12.0 mA (10
trasher [3.6K]

Answer:

b. 375 Ohms

Explanation:

<u>Given the following data;</u>

Voltage = 4.5 V

Current = 12 mA

To find the resistance;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

V = IR

Where;

  • V represents voltage measured in voltage.
  • I represents current measured in amperes.
  • R represents resistance measured in ohms.

<u>Conversion:</u>

1000 mA = 1 A

12 mA = 12/1000 = 0.012 A

R = \frac {V}{I}

Substituting into the formula, we have;

R = \frac {4.5}{0.012}  

Resistance, R = 375 ohms

6 0
3 years ago
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