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Andreas93 [3]
3 years ago
8

What is the height of the cliff?

Physics
1 answer:
Lerok [7]3 years ago
3 0
To find the height of the cliff
use the kinematical equation
height = 1/2*a*t^2
= 5*0.75*0.75 = 2.8125 m
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Light is an electromagnetic wave and travels at a speed of 3.00 × 108 m/s. The human eye is most sensitive to yellow-green light
Nimfa-mama [501]

Answer:

f = 5.95 \times 10^{14} Hz

Explanation:

As we know that the frequency of the wave is given as

f = \frac{c}{\lambda}

here we know that

c = 3 \times 10^8 m/s

also we know that

\lambda = 5.04 \times 10^{-7} m

now we have

f = \frac{3 \times 10^8}{5.04 \times 10^{-7}}

f = 5.95 \times 10^{14} Hz

6 0
3 years ago
man stands on a platform that is rotating (without friction) with an angular speed of 1.2 rev/s; his arms are outstretched and h
-Dominant- [34]

Answer:

w₂ = 22.6 rad/s

Explanation:

This exercise the system is formed by platform, man and bricks; For this system, when the bricks are released, the forces are internal, so the kinetic moment is conserved.

Let's write the moment two moments

initial instant. Before releasing bricks

       L₀ = I₁ w₁

final moment. After releasing the bricks

       L_{f} = I₂W₂

       L₀ = L_{f}

       I₁ w₁ = I₂ w₂

       w₂ = I₁ / I₂ w₁

let's reduce the data to the SI system

     w₁ = 1.2 rev / s (2π rad / 1rev) = 7.54 rad / s

 

 let's calculate

       w₂ = 6.0/2.0   7.54

       w₂ = 22.6 rad/s

3 0
3 years ago
How are steam powered boats different from sailboats
Alex
Steam powered boats run from an engine, using power, gears, and cranks to function.

Sailboats use no engine and rely on winds to move and change the direction of the boat. 
3 0
3 years ago
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klasskru [66]

Answer:

50.8 watt

Explanation:

we know that P=W÷t

W=F.S           S-->distance=50 ft= 15.24 m

F=ma

=100×10=1000 N

SO W= 1000×15.24

        =15240 J

NOW

P=W÷t          t=5 mints = 5×60=300 sec

P=15240÷300

P=50.8 watt

8 0
3 years ago
Mars has twice the mass of Mercury and is 4 times further away from the Sun. Calculate theratio of the gravitational force from
svetoff [14.1K]

Answer:

F(Mars) = 2 G m M / (4 R)^2   force of Sun on Mars

F(Merc) = G m M / R^2    force of force of Sun on Mercury

R = distance of Sun from Mercury, m = mass of Mercury

F(Merc) / F(Mars) = 4^2 / 2 = 8

6 0
2 years ago
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