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Andreas93 [3]
3 years ago
8

What is the height of the cliff?

Physics
1 answer:
Lerok [7]3 years ago
3 0
To find the height of the cliff
use the kinematical equation
height = 1/2*a*t^2
= 5*0.75*0.75 = 2.8125 m
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Why us an element considered a pure substance
AVprozaik [17]

Explanation:

Hey there!!

An elements is called a pure substance because it is composed of only one kina of atoms in a fix proportion.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
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What is the difference between a star and a planet.
balandron [24]

Answer:  In the planet there is life and the star is a store of energy where the planet gets its light, life and energy.

Explanation:

5 0
2 years ago
Rachel has been reading her physics book. She takes her weighing scales into an elevator and stands on them. If her normal weigh
GrogVix [38]

Answer:

345 N

Explanation:

Given:

Normal weight of Rachel (mg) = 690 N

Case 1: Upward motion of elevator

Given:

Acceleration of elevator (a) = 0.25 g

The scale reading is given by the normal force acting on Rachel. Let N₁ be the normal force.

So, the net force acting on Rachel is given as:

F_{net}=N_1-mg=N_1-690

Now, from Newton's second law:

F_{net}=ma\\\\N_1-690=m\times 0.25g\\\\N_1-690=0.25\times (mg)\\\\N_1-690=0.25\times 690\\\\N_1=690+172.5=862.5\ N------(1)

Case 2: Downward motion of elevator

Given:

Acceleration of elevator (a) = 0.25 g

The scale reading is given by the normal force acting on Rachel. Let N₂ be the normal force.

So, the net force acting on Rachel is given as:

F_{net}=mg-N_2=690-N_2

Now, from Newton's second law:

F_{net}=ma\\\\690-N_2=m\times 0.25g\\\\690-N_2=0.25\times (mg)\\\\690-N_2=0.25\times 690\\\\N_2=690-172.5=517.5\ N------(2)

Now, the difference in the scale reading is obtained by subtracting equation (2) from equation (1). This gives,

Difference=N_1-N_2=862.5-517.5=345\ N

Therefore, the difference between the up and down scale readings is 345 N.

4 0
3 years ago
If the mass of a material is 114 grams and the volume of the material is 13 cm3, what would the density of the material be?
laila [671]
114/13=m/v=d
d=8.7692 g/cm^3
4 0
3 years ago
93 cm3 liquid has a mass of 77 g. When calculating its density what is the appropriate number of significant figures
lubasha [3.4K]

Answer:

828 kg/m³ or 0.828 g/cm³

Explanation:

Applying,

D = m/V............. Equation 1

Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.

From the question,

Given: m = 77 g , V = 93 cm³

Substitute these values into equation 1

D = 77/93

D = 0.828 g/cm³

Converting to kg/m³

D = 828 kg/m³

6 0
3 years ago
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