Answer:
Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.
Explanation:
We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.

The values of the velocities are,


We know that the acceleration is equivalent to the change of the speed in a certain time therefore



Now applying the Newton's second law we have,



Therefore the approximate magnitude is 8516.36N
The formula that we will going to use in this question is simply P1V1/T1 = P2V2/T2 where T is the constant.
P1V1 = P2V2
P2 = P1V1/V2 = (V1 / V2) x P2 = (13.0 L / 6.5 L) x 0.76 atm = 1.5 atm
The answer in this question is 1.5 atm
Answer:
The work done on the object by the force in the 5.60 s interval is 40.93 J.
Explanation:
Given that,
Force 
Mass of object = 2.00 kg
Initial position 
Final position 
Time = 4.00 sec
We need to calculate the work done on the object by the force in the 5.60 s interval.
Using formula of work done


Put the value into the formula




Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.