I believe the answer is a: cells.
<span>h ( t) = h(1 sec) = -16t^2 + 541
so h (2 sec) = -16*(2)^2 + 541 = -64 + 541 = <span>477 ft
Therefore, </span></span>the height of the rock after 2 seconds is 477 feet.
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Answer:
Yes! im not sure if this is correct :)
Explanation:
Answer:
The total distance the bird travels is d.
Explanation:
Each train travels at the speed s. They will meet at the center, a distance d/2 (which is where the bird might be crushed). Each train travels the same distance d/2 in a time t which is also equal for both. This is also the time the bird spends travelling between them.
For any of the train, the time t is the distance divided by the speed.
The bird travels at the speed of 2s. Its distance is given by the product of its speed and the time taken.
Answer:
Explanation:
Speed of electron
v = 4 × 10^5 •j m/s
Magnetic field
B = 5 × 10^-5 T at angle of 45° to horizontal
Charge of electron
q = 1.6 × 10^-19C
Magnitude of force F?
The Force exerted in an electric field is given as
F = q(v×B)
Now, x component of the magnetic field
Bx = BCos45 = 5×10^-5 Cos45
Bx = 3.54 × 10^-5 •i T
Also, y component
By = BSin45 = 5 × 10^-5Sin45
By = 3.54 × 10^-5 •j T
B = 3.54 × 10^-5 •i + 3.54 × 10^-5 •j T
Now, F = q(v×B)
Note that,
i×i=j×j=k×k=0
i×j =k, j×k = i, k×i = j
j×i = -k, k×j = -i and i×k = -j
Therefore
F = q(v×B)
F = 1.6×10^-19(4×10^5•j × (3.54 × 10^-5 •i + 3.54 × 10^-5 •j T))
F = 1.6×10^-19 (4×10^5 × 3.54 × 10^-5 (j×i) + 4×10^5 × 3.54 × 10^-5(j×j))
F = 1.6×10^-19(14.14(-k) + 0)
F = —2.26 × 10^-18 •k N
It is in the negative direction of z axis
The magnitude of the force the field experience is 2.26 × 10^-18 N