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3 years ago

(a+7)2 please expand it

Mathematics

2 answers:

labwork [276]3 years ago

8 0

I think it actually means (a+7)(a+7) so it would be: a^2 + 14a + 49

sergiy2304 [10]3 years ago

3 0

Answer:

expand (a + 7) * 2: 2a + 14

Step-by-step explanation:

(a + 7) * 2

= 2 ( a + 7)

apply the distributive law: a(b + c) = ab + ac

a = 2, b = a, c = 7

= 2a + 2 * 7

multiply the numbers: 2 * 7 = 14

= 2a + 14

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Kaira's gross pay is $4,633. Her deductions total $1,009.13. What percent of hergross pay is take-home pay?Round to the nearest

Delvig [45]

Answer:

$\text{ 78\%}$

Explanation:

Here, we want to get the percentage of the gross pay is the take-home pay

Mathematically, we have to divide the take-home pay by the gross pay and multiply it by 100%

Her take-home pay is the difference between her gross pay and her deductions

We have this as:

$\text{ 4633 - 1009.13 = \$3,623.87}$

We have this as:

$\frac{3623.87}{4633}\text{ }\times\text{ 100 \% = 78\%}$

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1 year ago

Use benchmarks to estimate the difference of<br> 9/11-2/14

soldier1979 [14.2K]

$\frac{9}{11} - \frac{2}{14} = \frac{9}{11} - \frac{1}{7} = \frac{63 - 11}{77} = \\ = \frac{52}{77}$

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3 years ago

Answer in 5 min I GIVE U BRAINLIEST

telo118 [61]

This is the formula of finding the hypotenuse: a² + b² = c².

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7 0

3 years ago

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algol [13]

$f\left(\dfrac\beta2\right)=\sin\dfrac\beta2$

Recall the half-angle identity:

$\sin^2\dfrac\beta2=\dfrac{1-\cos\beta}2\implies\sin\dfrac\beta2=\pm\sqrt{\dfrac{1-\cos\beta}2}$

So in order to find $f\left(\dfrac\beta2\right)$ , we only need to know the value of $\cos\beta$ . But there are two possible values. To decide which to take, we use the given information: we know that $\beta$ lies in quadrant III, which means $\pi$ , so $\dfrac\pi2$ , which places $\dfrac\beta2$ in quadrant II. In this quadrant, the sine of angle is positive, and so

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\cos\beta}2}$

$\beta$ is an angle of a ray whose terminal point, $\left(-\dfrac13,y\right)$ lies on the circle $x^2+y^2=1$ . The $x$ -coordinate is all we need to know in order to find that $\cos\beta=-\dfrac13$ . So,

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\left(-\frac13\right)}2}=\sqrt{\dfrac46}=\dfrac{\sqrt2}{\sqrt3}=\dfrac{\sqrt6}3$