Question

A plane passes over point a with a velocity of 5000 m/s north. Sixty seconds later it passes over point b at a velocity of 10,000 m/s north. What is the plane’s acceleration from A to B?

Answer 1

Answer:

The plane’s acceleration from A to B is

$a =83.33\ m/s^2$

Explanation:

The acceleration of an object is a measure of how its speed changes over time.

In this case, we know that the plane initially has a velocity of 5000 m/s when it passes through point A, and when it passes through point B, 60 seconds later it has a velocity of 10,000 m/s.

Then the average acceleration is calculated as

$a =\frac{s_2-s_1}{t_2-t_1}$

Where

$s_2 = 10 000$ is the final speed

$s_1=5000$ is the initial velocity

$t_2 -t_1=60$ is the time it took for the object to reach the final speed

Then

$a =\frac{10000-5000}{60}$

$a =\frac{5000}{60}$

$a =83.33\ m/s^2$