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Neporo4naja [7]
3 years ago
14

A train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity​

Physics
1 answer:
Kobotan [32]3 years ago
7 0

Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

v = u + at

v = 44 + (-4 x 10)

v = 44 - 40

v = 4 m/s

Therefore, the final velocity of the train is 4 m/s.

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soldier1979 [14.2K]

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<h2>What is disorganized schizophrenia?</h2>

Disorganized schizophrenia is the disease expressed through hallucinations and delusions, among the negative symptoms we find cognitive, behavioral and emotional deficits of different types.

<h3>Symptoms of disorganized schizophrenia</h3>

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Therefore, we can conclude that the presence of inappropriate emotional expressions, disorganized language, and motivational deficits are symptoms of disorganized schizophrenia.

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A 15.0 g bullet is moving to the right with speed 270 m/s when it hits a target and travels an additional 25.0 cm into the targe
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Answer:

F=2187\ N

Explanation:

Given:

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  • initial velocity of bullet, u=270\ m.s^{-1}
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Here as given in the question the bullet penetrates the target by the given displacement of the bullet into it. During this process it faces deceleration and hence it comes to rest.

  • so, final velocity of the bullet, v=0\ m.s^{-1}

Now using the equation of motion:

v^2=u^2+2a.s

where:

a= acceleration of the bullet

0^2=270^2+2a\times 0.25

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S_E(t)=V_E t=(V_S+3)t
S_S(t)=V_S t


2) After a time t=3~h, the two boats are 45~mi apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:
S_E(3~h)=3(V_S+3)=3V_S+9
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The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which S_E and S_S are the two sides. Therefore, we can use Pythagorean theorem and write:
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