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dybincka [34]
3 years ago
10

Determine how many moles of copper(ii) chloride are in 15.00 ml of a 0.500m solution.

Chemistry
2 answers:
julia-pushkina [17]3 years ago
7 0
Answer : To calculate the number of moles of copper (II) chloride in 15.0 ml of 0.500 M solution, you have to simply use the given calculation:

15 (ml)   X   0.500 (moles) / 1000 (mL) = <span>0.00750 moles of CuCl₂ .
</span>

nataly862011 [7]3 years ago
4 0

Answer: The number of moles of Copper (II) chloride is 0.0075mol.

Explanation:

From the definition of molarity, it is the number of moles of solute in 1L or 1dm³ of a solution. It has the unit of mol/dm³ or mol/L or simply M

It can be expressed as

Molarity = moles of solute / volume of solution

Given that ;

molarity =0.50M

Volume of solution =15mL= 15× 10^-3

moles of solute (Copper (II) Chloride) =?

0.50 = moles of solute /15×10^-3

Moles = 0.50 × 15×10^-3

Moles = 7.5 ×10^-3mole

Therefore moles of Copper (II) chloride = 0.0075mol.

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Answer:

The Kc of this reaction is 311.97

Explanation:

Step 1: Data given

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