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laiz [17]
3 years ago
11

Which kind of magma produces a quiet volcanic eruption

Chemistry
2 answers:
Zina [86]3 years ago
8 0
Magma rich in silica is the answer i have
Ilia_Sergeevich [38]3 years ago
3 0
Mafic lava is low viscosity lava that creates quiet eruptions.

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During an effusion experiment, a certain number of moles of an unknown gas passed through a tiny hole in 50 seconds. Under the s
mafiozo [28]
50/35 = √x/ √31.9988 g
50 x (√31.9988/ 35) = √x

√x = 8.081...

x= 65.30...

x= 70 g/ mol


3 0
2 years ago
What is the force that holds atoms together
ololo11 [35]

Explanation:

Chemical bond refers to the forces holding atoms together to form molecules and solids. This force is of an electric nature, and the attraction between electrons of one atom to the nucleus of another atom contributes to what is known as chemical bonds.

7 0
2 years ago
7. Which of the following pairs of elements is most likely to form an ionic
yaroslaw [1]

Answer:

not sure if this us right but oxygen and fluorine? I learned chem but I forgot about it kinda sorry

5 0
3 years ago
Pentaborane-9, B5H9, is a colorless, highly reactive liquid that will burst into flame when exposed to oxygen. The reaction is 2
mina [271]

<u>Answer:</u> The amount of energy released per gram of B_5H_9 is -71.92 kJ

<u>Explanation:</u>

For the given chemical reaction:

2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(5\times \Delta H^o_f_{(B_2O_3(s))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(2\times \Delta H^o_f_{(B_5H_9(l))})+(12\times \Delta H^o_f_{(O_2(g))})]

Taking the standard enthalpy of formation:

\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol\\\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(5\times (1271.94))+(9\times (-285.83))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H^o_{rxn}=-9078.57kJ

We know that:

Molar mass of pentaborane -9 = 63.12 g/mol

By Stoichiometry of the reaction:

If 2 moles of B_5H_9 produces -9078.57 kJ of energy.

Or,

If (2\times 63.12)g of B_5H_9 produces -9078.57 kJ of energy

Then, 1 gram of B_5H_9 will produce = \frac{-9078.57kJ}{(2\times 63.12)}\times 1g=-71.92kJ of energy.

Hence, the amount of energy released per gram of B_5H_9 is -71.92 kJ

8 0
3 years ago
How do you express 0.00026 in scientific notation
Rus_ich [418]
2.6x10negative4power 2.6x10^-4
6 0
3 years ago
Read 2 more answers
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