Which kind of magma produces a quiet volcanic eruption

What is the correct name of this compound?

Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

8 0

3 years ago

If the atmospheric pressure in the laboratory is 1.2 atm, how many moles of gas were in each syringe? (Hint: Choose one volume a

Naily [24]

Answer:

A: 2.525 x 10-4 mol

B: 2.583 x 10-4 mol

Explanation:

Part A:

Data Given:

. Temperature of water (H2O) = 21.3°C

Convert Temperature to Kelvin

T = °C + 273

T = 21.3 + 273 = 294.3 K

volume of (H2O) gaseous state = 5.1 mL

Convert mL to liter

1000 mL = 1L

5.1 ml = 5.1/1000 = 0.0051 L

Pressure = 1.2 atm

. no. of moles = ?

Solution

no. of moles can be calculated by using ideal gas formula

PV = nRT

Rearrange the equation for no. of moles

n=PV/RT......... (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

where

R = 0.08206 L.atm/ mol. K

Now put the value in formula (1) to calculate no. of moles of

n = 1.2 atm x 0.0051 L / 0.08206 L.atm.mol-1. K-1 x 294.3 K

n = 0.0061 atm.L / 24.162 L.atm.mol-1

n = 2.525 x 10-4 mol

no. of moles of gas (H2O) = 2.525 x 10-4 mol

Part B:

Data Given:

Temperature of water (H2) = 21.3°C

Convert Temperature to Kelvin

T = "C + 273

T= 21.3 + 273 = 294.3 K

volume of (H2) gas = 5.2 mL

Convert mL to liter

1000 mL = 1 L

5.2 ml = 5.2/1000 = 0.0052 L

Pressure = 1.2 atm

. no. of moles = ?

Solution

no. of moles can be calculated by using ideal gas formula

PV = nRT

Rearrange the equation for no. of moles

n= PV / RT......... (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

where

R = 0.08206 L.atm/mol. K

Now put the value in formula (1) to calculate no. of moles of

n = 1.2 atm x 0.0052 L/0.08206 L.atm.mol-1. K-1 x 294.3 K

n = 0.0062 atm.L/ 24.162 L.atm.mol-1

n = 2.583 x 10-4 mol

I

no. of moles of gas (H2) = 2.583 x 10-4 mol

8 0

3 years ago

In the Haber process for the production of ammonia, what is the relationship between the rate of production of ammonia and the r

tangare [24]

Answer:

Δ[NH₃]/Δt = 2/3 ( Δ[H₂]/Δt )

Explanation:

For determining rates as a function of reaction coefficients one should realize that these type problems are always in pairs of reaction components. For the reaction N₂ + 3H₂ => 2NH₃ one can compare ...

Δ[N₂]/Δt ∝ Δ[H₂]/Δt, or

Δ[N₂]/Δt ∝ Δ[NH₃]/Δt, or

Δ[H₂]/Δt ∝ Δ[NH₃]/Δt, but never 3 at a time.

So, set up the relationship of interest ( ammonia rate vs. hydrogen rate)... nitrogen rate is ignored.

Δ[H₂]/Δt ∝ Δ[NH₃]/Δt

Now, 'swap' coefficients of balanced equation and apply to terms given then set term multiples equal ...

N₂ + 3H₂ => 2NH₃ => 2(Δ[H₂]/Δt) = 3(Δ[NH₃]/Δt) => 2/3(Δ[H₂]/Δt) = (Δ[NH₃]/Δt)

NOTE => Comparing rates individually of the component rates in reaction process, the rate of H₂(g) consumption is 3/2 times faster than NH₃(g) production (larger coefficient). So, in order to compose an equivalent mathematical relationship between the two, one must reduce the rate of the H₂(g) by 2/3 in order to equal the rate of NH₃(g) production. Now, given the rate of one of the components as a given, substitute and solve for the unknown.

CAUTION => When Interpreting rate of reaction one should note that the rate expression for an individual reaction component defines 'instantaneous' rate or speed. This means velocity (or, speed) does not have 'signage'. Yes, one may say the rate is higher or lower as time changes but that change is an acceleration or deceleration for one instantaneous velocity to another. Acceleration and Deceleration do have signage but the positional instantaneous velocity (defined by a point in time) does not. Thus is reason for the 'e-choice' answer selection without the signage associated with the expression terms.

3 0

2 years ago

Read 2 more answers

Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reac

monitta

Answer:

75.5 g O₂ (g) can be produced from 42.6 g of H₂O (g)

Explanation:

1) Balanced chemical equation (given):

2H₂O(g) → 2H₂(g) + O₂(g)

2) Mole ratios:

2 moles H₂O(g) : 2 moles H₂(g) : 2 moles O₂(g)

3) Calculate the number of moles of reactant (H₂0):

number of moles = mass in grams / molar mass

molar mass of water: 18.015 g/mol

mass in grams of water: 42.6 g

number of moles = 42.6 g / 18.05 g/mol = 2.36 moles H₂O

4) Set a proportion using the mole ratio O₂ to H₂O and the actual number of moles of H₂O:

2 moles O₂ / 2 moles H₂O = x / 2.36 moles H₂O

x = 2.36 moles O₂

5) Convert 2.36 moles O₂ to grams:

mass in grams = number of moles × molar mass

mass = 2.36 moles × 32.00 g/mol = 75.5 g O₂

4 0

3 years ago

Read 2 more answers

In terms of energy of reaction, explain how a cold compress used by an athlete works.

Alex17521 [72]

Answer:

Cold and compression have long been used to help sports injuries. The use of cold helps in reducing pain and swelling, while compression works to reduce edema.

7 0

3 years ago