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maxonik [38]
3 years ago
12

Which molecule has the same empirical formula as molecular formula?

Chemistry
1 answer:
statuscvo [17]3 years ago
5 0

the answer is C ( i think )

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Taya2010 [7]
Answer : A. Location A

The seats in location A will experience sound waves with the greatest intensity , because it is closer to the stage .
7 0
2 years ago
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A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?
RSB [31]
PH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is <u>acidic</u>.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic
5 0
3 years ago
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You are given three beakers of unknown liquids. One beaker contains sugar water. Without tasting the liquids, how could you iden
Marrrta [24]

You would observe, trying to identify if there's a minimum difference in each beaker. Like, colour, or using an <em>bagueta </em>(idk how to say it in english), churning it or something like that.

8 0
3 years ago
When 0.422g of phosphorus is burned, 0.967g of a white oxide is obtained.
nata0808 [166]
Moles = mass / molar mass 

<span>moles P = 0.422 g / 30.97 g/mol = 0.01363 mol </span>
<span>moles O = (0.967 g - 0.422g) / 16.00 g/mol = 0.03406 moles </span>

<span>So ratio moles P : moles O </span>
<span>= 0.01363 mol : 0.03406 mol </span>

<span>Divide each number in the ratio by the smallest number </span>

<span>(0.01363 / 0.01363) : (0.03406 / 0.01363) </span>
<span>= 1 : 2.5 </span>

<span>The empirical formula needs to be the smallest whole number ratio of atoms in the molecules. Since you have a non-whole number, multiply the ratio by the smallest number needed to make both number whole numbers. In this case x 2 </span>

<span>2 x (1 : 2.5) </span>
<span>= 2 : 5 </span>
5 0
3 years ago
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a 45g sample of water at 12°c is heated with 15kJ of energy. What will be the final temperature of the water?
Marizza181 [45]

Answer:

Final temperature  = 91.75  °C

Explanation:

Given data:

Mass of water = 45 g

Initial temperature = 12 °C

Energy required = 15 Kj (15000 j)

Final  temperature = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

15000 j = 45 g × 4.18 j/g.°C × (T2 -T1)

15000 j = 45 g × 4.18 j/g.°C × (T2-  12 °C)

15000 j = 188.1 J/°C × (T2-  12 °C)

15000 j / 188.1 J/°C = T2-  12 °C

79.745 °C  = T2 - 12 °C

T2 = 79.745 °C +  12 °C

T2 = 91.75  °C

4 0
3 years ago
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