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lapo4ka [179]
4 years ago
6

solve algebraically: the soccer field has an area of 6000 square yards. The field is 40 yards longer than its width. What are th

e dimensions of the field in years
Mathematics
1 answer:
JulijaS [17]4 years ago
5 0
The dimensions are 60 yards by 100 yards
Proof:
Let the wdth be x and the length be x+40
x(x+40)=6000
x²+40x=6000
x²+40x-6000=0
use the quadratic formula
x= -40+ or - √40²-4*1*-6000
x= 60, -100
but distance but be positive so the dimensions are 60 yards by 100 yards
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Answer:

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<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

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