Answer:
a. Magnetic Field =1.997× T
b. Area= 2.68×
Magnetic Flux= 5.367×T
c. Inductance= 6.013×H
Explanation:
Parameters from the question
I= 44.5×A
N=500 turns
Diameter=18.5mm
Radius = (diameter/2) = 9.25mm =9.25×m
L= 14cm = 0.14m
Permitivity <u></u>=4π×H/m
The Formulars Used are
B(Magnetic Field) =
Mag Flux= B.A
Inductance=
Answer:
Explanation:
Given
mass of chair m=21 kg
Force required to set chair in motion is 175 N
Once the chair is in motion 137 N is require to move it with constant velocity
i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force
thus
where is the coefficient of static friction and N is Normal reaction
Answer:
electric energy ( power ) = 300000 W
Explanation:
given data
mechanical (hydroelectric) energy = 120 MJ/min = 2000000 J/s
efficiency = 15 % = 0.15
solution
we know that Efficiency of electric engine is expression as
Efficiency = Mechanical energy ÷ electric energy ......................1
and here dam electrical power output is
put here value in equation 1
electric energy ( power ) = Efficiency × Mechanical energy ( power )
electric energy ( power ) = 0.15 × 2000000 J/s
electric energy ( power ) = 300000 W
Law of universal gravitation:
F = GMm/r²
F = gravitational force, G = gravitational constant, M & m = masses of the objects, r = distance between the objects
F is proportional to both M and m:
F ∝ M, F ∝ m
F is proportional to the inverse square of r:
F ∝ 1/r²
Calculate the scaling factor of F due to the change in M:
k₁ = 2M/M = 2
Calculate the scaling factor of F due to the change in m:
k₂ = 2m/m = 2
Calculate the scaling factor of F due to the change in r:
k₃ = 1/(4r/r)² = 1/16
Multiply the original force F by the scaling factors to obtain the new force:
Fk₁k₂k₃
= F(2)(2)(1/16)
= F/4