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k0ka [10]
3 years ago
7

A car moves at 20 m s' for 15 minutes. Calculate the distance travelled

Physics
1 answer:
Firdavs [7]3 years ago
6 0

Explanation:

Calculating this according to the m/s rate

Now solving the question

If the car goes 20 m/s mathematically we can generate it as

15 × 60 = 600 secs

If the car goes 20 meters per every second it means

The car will go 20 meters for 900 secs

Which is 900 ×20 = 18000m/s

=18000÷1000 = 1km

Therefore the answer is 18km

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if a free falling rock were equipped with a speedometer, by how much would it's speed readings increase with each second IF it w
Kaylis [27]
Accelleration(a) is changing of velocity in second.
free fall a = g
speed increase = a = g = 20 (m/s) / s
7 0
3 years ago
The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca
Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J

Calculating point A:

when the value is 0.38

\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\

                   =2.632

\to D(a.v) = \frac{1}{0.38} \times 206265\\

               =542,802.6

Calculating point B:

when the value is 0.75

\to D(PC)=\frac{1}{0.75}

                =1.33

\to D(a.v) = \frac{1}{0.75} \times 206265\\

             =275,020

Calculating point C:

when the value is 0.28

\to D(PC)=\frac{1}{0.28}

                =3.571

\to D(a.v) = \frac{1}{0.28} \times 206265\\

               =736660.7

Calculating point D:

when the value is 0.42

\to D(PC)=\frac{1}{0.42}

                =2.38

\to D(a.v) = \frac{1}{0.42} \times 206265\\

               =490910.7

Calculating point E:

when the value is 0.31

\to D(PC)=\frac{1}{0.31}

                =3.226

\to D(a.v) = \frac{1}{0.31} \times 206265\\

               =665370.97

6 0
3 years ago
A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 15-m-long cable. You are (un
Charra [1.4K]

Answer:

1.9 s

Explanation:

We are given that

Length of cable=l=15 m

We have to find the time you have to move out of the way.

We know that

Time period,T=2\pi\sqrt{\frac{l}{g}}

Where g=9.8m/s^2

By using the formula

T=2\pi\sqrt{\frac{15}{9.8}}

T=2\times 3.14\times \sqrt{\frac{15}{9.8}}=7.77 s

Time you have to move out

t=\frac{T}{4}=\frac{7.77}{4}=1.9 s

Hence,time you have to move out of the way=7.77 s

6 0
3 years ago
Calculate the average speed in metres per second from Glasgow to Ediburgh ( The table )
Angelina_Jolie [31]
Total distance is 28+12+34=74km=74000m.
Total time is 20+8+25 minutes=53 minutes=53×60=3180 secs.
Average speed is 74000/3180=23.27 m/s.
7 0
3 years ago
On average how fast does the radiation spread from an atom-bomb?
devlian [24]

Answer:

around 30 grays

Explanation:

Hope this helps :)

7 0
3 years ago
Read 2 more answers
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