Ask question

Ask question

All categories

4 years ago

12

The two loudspeakers in the drawing are producing identical sound waves. The waves spread out and overlap at the point P. What i

s the difference in the two path lengths if point P is at the third sound intensity minimum from the central sound intensity maximum

1 answer:

Damm [24]4 years ago

5 0

Answer:

5/2π

Explanation:

According to quizlet the answer is 5/2π

You might be interested in

An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50

sasho [114]

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

t_m = T - t_p

t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

d = V*t_m

- Where speed of light in silicon medium is given by:

V = c / n

- Hence, d = c*t_m / n

-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50

d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

8 0

3 years ago

gas is compressed by a piston in a cylinder from an initial pressure of 1.0 bar and initial volume of 0.4m3 , to a final pressur

Ket [755]

The work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

<h3>What is work done by gas?</h3>

When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.

Given data;

Initial pressure(P₁)=1.0 bar

The initial volume, V₁=0.4m³

Final pressure(P₂) =1.4 bar.

work is done on the gas., W=?(-ve)

Heat release= - 8.1 kJ

Change in the internal energy of the gas., ΔE

During the compression process, PV=C

P₁V₁=P₂V₂

1.0 bar × 0.4m³= 1.4 bar ×V₂

V₂=0.285 m³

$\rm W=P_1V_1ln\frac{V_2}{V_1} \\\\\ \rm W=1.0 \times 0.4 ln\frac{0.285}{0.4} \\\\\ W=-13549 \ J$

The work done on the gas will be -13459 J.

The internal energy is found as;

ΔE=q+w

ΔE= -8.1 ×10³ -13549

ΔE=-21649 J

Hence, work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

To learn more about the work done by gas refer to;

brainly.com/question/12539457

#SPJ1

4 0

2 years ago

While using a digital radiography system, suppose a radiographer uses exposure factors of 10 mAs and 70 kVp with an 8:1 grid for

Nimfa-mama [501]

Answer:

b. 12.5 mAs, 70 kVp

Explanation:

The given parameter are;

The initial exposure factors := 10 mAs and 70 kVp

The initial Grid Ratio, G.R.₁ = 8:1

The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂ = 12:1

Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;

The GCF for G.R. 8:1 = 4

The GCF for G.R. 12:1 = 5

Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;

mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs

Therefore the new exposure factors are;

12.5 mAs, 70 kVp

5 0

3 years ago

What type of tide occurs when the Sun, Earth and Moon are aligned with one another?

nlexa [21]

Answer:

spring tides

Explanation:

8 0

3 years ago

Read 2 more answers

A car moves from the point (3.0 m)x^ + (5.0 m)y^ to the point (8.0 m)x^ - (7.0 m)y^ in 2.0 s. what is the magnitude of the avera

Mandarinka [93]

8.0-3.0=5.0metres in the x direction
7.0-5.0=2.0 metres in the y direction
Use Pythagoras
25+4=29
$\sqrt[2]{29 }$
=5.39metres in 2secs
=2.645m/s at an angle of 68.2 degrees to horizontal.... see below!
tan-1 angle = 5/2
angle=68.2 degrees

4 0

4 years ago