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Black_prince [1.1K]
3 years ago
15

Put the steps of the scientific method into the correct order.

Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:define propose devise state and then submit

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Its a more then one answer can u help me
Lady bird [3.3K]
The answers would be
1.b
2.c
3.a
6 0
3 years ago
how many grams of barium sulfate are produced if 10.0 grams of barium chloride are reacted is excess sulfuric acid​
kow [346]

Answer: 11.2 grams

Explanation:

The balanced chemical equation for reaction is:

BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of BaCl_2

\text{Number of moles}=\frac{10.0g}{208.23g/mol}=0.0480moles

According to stoichiometry :

As sulfuric acid​ is in excess , the limiting reagent is barium chloride as it limits the formation of product.

1 mole of BaCl_2 produces=  1 mole of BaSO_4

Thus 0.0480 moles of BaCl_2 require=\frac{1}{1}\times 0.0480=0.0480moles  of BaSO_4

Mass of BaSO_4=moles\times {\text {Molar mas}}=0.0480mol\times 233.38g/mol=11.2g

Thus 11.2 g of barium sulfate are produced if 10.0 grams of barium chloride are reacted is excess sulfuric acid​

7 0
3 years ago
Uranium-235 and uranium-238 are considered isotopes of one another
Aliun [14]
I'm confused so I'm assuming that you want to know why, so its because they have a different number of neutrons. Hope I helped if not please update your question.
4 0
3 years ago
Which of the following compounds, when placed in water, would NOT allow
igomit [66]

Answer:

Sucrose (C12H22011)  will not let a lightbulb light in water

Explanation:

Sucrose is too soluble to allow a lightbulb to light.

5 0
3 years ago
Determine the [H+] or [OH−] for each of a solutions at 25°C.
levacccp [35]

Answer:

Solution B: [OH-] = 1×10^–6 M

Solution C: [OH-] = 1×10^–6 M

Explanation:

Solution B:

Hydronium ion concentration, [H3O+] = 9.99×10^–9 M

Hydroxide ion concentration, [OH-] = ?

The Hydroxide ion concentration, [OH-] can be obtained as follow:

[H3O+] × [OH-] = 1×10^–14

9.99×10^–9 × [OH-] = 1×10^–14

Divide both side by 9.99×10^–9

[OH-] = 1×10^–14 / 9.99×10^–9

[OH-] = 1×10^–6 M

Therefore, the Hydroxide ion concentration, [OH-] is 1×10^–6 M

Solution C:

Hydronium ion concentration, [H3O+] = 0.000777 M

Hydroxide ion concentration, [OH-] = ?

The Hydroxide ion concentration, [OH-] can be obtained as follow:

[H3O+] × [OH-] = 1×10^–14

0.000777 × [OH-] = 1×10^–14

Divide both side by 0.000777

[OH-] = 1×10^–14 / 0.000777

[OH-] = 1.29×10^–11 M

Therefore, the Hydroxide ion concentration, [OH-] is 1.29×10^–11 M

6 0
3 years ago
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