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exis [7]
3 years ago
15

A two-phase, liquid–vapor mixture of h2o, initially at x 5 30% and a pressure of 100 kpa, is contained in a piston– cylinder

assembly, as shown in fig p3.77. the mass of the piston is 10 kg, and its diameter is 15 cm. the pressure of the surroundings is 100 kpa. as the water is heated, the pressure inside the cylinder remains constant until the piston hits the stops. heat transfer to the water continues at constant volume until the pressure is 150 kpa. friction between the piston and the cylinder wall and kinetic and potential energy effects are negligible. for the overall process of the water, determine the work and heat transfer, each in kj.
Physics
1 answer:
Andrew [12]3 years ago
7 0
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
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A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?
STatiana [176]
Power = Force * Distance/ time
P = 1,250 * 2/3
P = 2,500/3
P = 833.33 Watts

So, your final answer is 833.33 Watts
5 0
3 years ago
Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis
WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

Where:

F is the gravitational force between Earth and Moon

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant  

M=5.972(10)^{24} kg is the mass of the Earth

m=7.349(10)^{22} kg is the mass of the Moon

r=3.9(10)^{8} m is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to F:

F=m.a_{C} (2)

Where a_{C} is the centripetal acceleration given by:

a_{C}=\frac{V^{2}}{r} (3)  

Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

\frac{V^{2}}{r}=G\frac{M}{r^{2}} (6)  

Finding V:

V=\sqrt{\frac{GM}{r}} (7)

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}} (8)

Finally:

V=1010.92 m/s

5 0
3 years ago
Two people travel from Columbus to Cleveland, one by car at an average velocity of 90km/h, and one by plane at an average veloci
Flura [38]

Answer:

Explanation:

Yes , their displacement may be equal .

Suppose the displacement is AB where A is starting point and B is end point .

The car is covering the distance AB by going from A to B on straight line . On the other hand plane goes from A to C , then from C to D and then from D to B . In this way plane reaches B from A on a different path which is longer than path of the car . In the second case also displacement of plane is AB . In the second case distance covered is longer but displacement is same that is AB .

7 0
3 years ago
Rjejdndjoskdnrksjdjsjsne
Ilia_Sergeevich [38]
Rjejdndjoskdnrksjdjsjsne
4 0
3 years ago
An astronaut has a mass of 90 kg. The astronaut travels to Mars, where gravity is weaker. The acceleration of free fall on the s
marin [14]

Answer:

w = mg

w = 90 * 3.7

w = 333 N

hope it helps you

3 0
2 years ago
Read 2 more answers
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