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3 years ago

For an object to be seen, light must leave _ and enter _.

Physics

1 answer:

amm18123 years ago

4 0

The answers are going to be reflects and rays?? hope that helped.

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How can a person detect infrared rays without an instrument?

natita [175]

So we want to know how can we detect infrared rays without an instrument. Infrared rays or heat, are a part of electromagnetic spectrum. We have specialized nerve cells in our skin called thermoreceptors that can detect differences in temperature that are produced by infrared part of EM spectrum.

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2 years ago

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On physical science so what is Forcewhat is force and its unit

ivann1987 [24]

Answer:force is an agent which change the state of rest or uniform motion of a body. The unit of force newton

Explanation:

Force is that which change the state of rest or uniform motion of an object.the unit of force is newton or kgm/s^2

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2 years ago

30. The length of mercury thread when it is at 0°C, 100°C and at an unknown temperature 0 is 25mm, 225mm and 175mm respectively.

yulyashka [42]

Answer:

75°C

Explanation:

175−25/225−25=x−0/100−0

150/200=x/100

x=150×100/200

= 75°C

3 0

2 years ago

Why do we consider eyes, ears, and fingers as physical sensor

seraphim [82]

Answer:

because

Explanation:

because we need eye to see if you don't have eyes how you regnise some one

if you have ears how can you know who's voice is who's

if don't have fingers how can you know what your are holding this is why they are called physical sensors

4 0

3 years ago

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A spring with a spring constant of 50 N/m is stretched 15cm. What is the force and energy associated with this stretching?

Olenka [21]

Data:
F (force) = ? (Newton)
k (<span>Constant spring force) = 50 N/m
x (</span>Spring deformation) = 15 cm → 0.15 m

Formula:
$F = k*x$

Solving:
$F = k*x$
$F = 50*0.15$
$\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark$

Data:
E (energy) = ? (joule)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m

Formula:
$E = \frac{k*x^2}{2}$

Solving:(Energy associated with this stretching)
$E = \frac{k*x^2}{2}$
$E = \frac{50*0.15^2}{2}$
$E = \frac{50*0.0225}{2}$
$E = \frac{1.125}{2}$
$\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark$

7 0

3 years ago

For an object to be seen, light must leave _______ and enter _______.

For an object to be seen, light must leave _ and enter _.