The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = 
m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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Answer:
C. Angular Separation
Explanation:
The term angular distance (or separation) is technically synonymous with angle itself, but is meant to suggest the (often vast, unknown, or irrelevant) linear distance between these objects (for instance, stars as observed from Earth).
Answer:
6 seconds
0.167 Hz
Explanation:
Distance = 4 m
Velocity = 0.75 m/s
Period is given by
The period of the motion is 3 seconds
Frequency is given by
The frequency of the motion is 0.33 Hz
Answer:
Stars are born within the clouds of dust and scattered throughout most galaxies. Deep within these clouds, turbulence creates knots with enough mass to cause the gas and dust to collapse under its own gravitational force.
