Answer:
517.5Ns
Explanation:
F=(MV - MU)/t
where MV - MU is the change in momentum,
therefore, MV - MU = Ft
= 345 X 1.
= 517.5Ns
Explanation:
It is given that,
A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.
Mass of the Sun,
Radius of Mercury's orbit,
Radius of discovered planet,
Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :
T = 4135214.625 s
or
T = 47.86 days
So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.
Answer:
height of a cliff is 45.86 m
Explanation:
u=8 m/s
t=2.35 s
the height of the cliff is