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Oksanka [162]
4 years ago
15

If your speed changes from 10 km/h to 6 km/h, you have a(n) ______ acceleration.

Physics
2 answers:
Delicious77 [7]4 years ago
8 0

If your speed changes from 10 km/h to 6 km/h then
you have an acceleration. 

Whether it's a positive or negative one completely depends
on which direction you decided to call the positive direction,
when you started considering your speed and its changes.

If you decided to call the direction in which you're traveling
the positive direction, then a decrease in your speed is a
negative acceleration. 

But you could just as easily have said that you're traveling
in the negative direction.  If you did that, then a decrease in
your speed would be a positive acceleration.

It's completely up to you, and how you define things.

Leona [35]4 years ago
7 0
If your speed changes from 10 km/h to 6 km/h, you have a(n) a.negative acceleration.

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Suppose that when you ride on your 7.50 kg bike the weight of you and the bike is supported equally by the two tires. If the gau
natali 33 [55]

Answer: 567 N

Explanation:

If the weight of the person and the bike are supported equally by the two tires, this means that the force acting on each tire, is half of the total weight.

We know that the gauge pressure in one tire, by definition, is equal to the force on the tire, over the contact surface between each tire and the road, so we can write:

P= F/A = (mrider g + mbike g) / A = (Fgrider + 7.5 kg. 9.8 m/s2) / 703 mm2 (1)

As the pressure data is given in lb/in2, it is needed to convert to N/mm2, as follows:

65.5 lb/in2 = 0.455 N/mm2.

Replacing in (1), and solving for  Fgrider, we have:

Fgrider = 567 N

4 0
3 years ago
A student runs 120 meters in 10 seconds. What is their speed? Question 6 options: 1.2 m/s 1200 m/s 120 m/s 12 m/s
aleksklad [387]

12m/s

Explanation:

Given parameters:

Distance run by student = 120 meters

Time = 10 seconds

Unknown:

Speed = ?

Solution:

Speed is the rate of change of distance with time:

       Speed = \frac{distance}{time}

Now input the parameters:

       Speed = \frac{120}{10} = 12m/s

Learn more:

Speed brainly.com/question/4581270

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5 0
4 years ago
a graph depicts force versus position. what represents the work done by the force over the given displacement?
atroni [7]
The area under the graph. W = f d cos(theta), so you want the number that is force times displacement, which corresponds to the area under the graph.
7 0
3 years ago
Un vas plin cu lichid cântăreşte 175kg. Ceea ce reprezintă de 5 ori masa vasului gol. Ştiind că volumul interior al vasului este
Mariana [72]

a) Density of the liquid: 823.5kg/m^3

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>

<em>a) the density of the liquid; </em>

<em>b) the weight of the liquid."</em>

a)

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

M=m_L + m_V (1)

where

m_L is the mass of the liquid

m_V is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg

which is the mass of the empty vessel.

Therefore, we can find the mass of the liquid only using (1):

m_L=M-m_V=175-35=140 kg

The density of the liquid is given by

d=\frac{m}{V}

where

m = 140 kg (mass of the liquid)

V = 0.170 kL = 170 L = 0.170 m^3 (volume of the liquid, which is equal to the volume of the vessel)

So we get

d=\frac{140}{0.170}=823.5kg/m^3

b)

The weight of a body is given by

F=mg

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

g=9.8 m/s^2 (acceleration due to gravity)

Therefore, its weight is

F=(140)(9.8)=1372 N

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

6 0
3 years ago
A hoodlum throws a stone vertically downward with an initial speed of 12.0 m/s from the roof of a building,30.0 m above the grou
bogdanovich [222]
S=ut +1/2at2
30=12t+1/2*10*t2
5t2+12t-30=0
8 0
3 years ago
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