Answer:
Velocity of a proton,
Explanation:
It is given that,
Potential difference, 
Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.
Using the conservation of energy as :

q is the charge of proton
m is the mass of proton




or

So, the velocity of a proton is
. Hence, this is the required solution.
Answer:
Hey, bro here is the explanation....
Explanation:
Hope it helps...
Answer:
This what they all been waiting for
I guess so
They been waiting for this sh,it for a long time didn't they
I'ma give it everything I got
Ayo Dougie park that X6 around the corner
Aye I'm just feeling my vibe right now
I'm feeling myself
Explanation:
Answer: Waning
Explanation: Not much explanation for this
<h3><u>Answer</u>;</h3>
≈ 5 Kgm²/sec
<h3><u>Explanation</u>;</h3>
Angular momentum is given by the formula
L = Iω, where I is the moment of inertia and ω is the angular speed.
I = mr², where m is the mass and r is the radius
= 0.65 × 0.7²
= 0.3185
Angular speed, ω = v/r
= (2 × 3.142 × r × 2.5) r
= 15.71
Therefore;
Angular momentum = Iω
= 0.3185 × 15.71
= 5.003635
<u>≈ 5 Kgm²/sec</u>