Answer:
Initial kinetic energy will be 2608200 lbf-ft
Initial speed will be 240.7488 m/sec
Explanation:
We have given height h = 900 ft
Mass of the object m = 90 lbm
Acceleration due to gravity 
Initial kinetic energy will be equal to potential energy of the object
So kinetic energy = potential energy = mgh 
This energy is also equal to the initial kinetic energy
So 

So initial velocity will be 240.7488 m/sec
Answer:
THES IS NOT
Explanation:
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You need to finish the question
Answer:
(B) 1.6 m/s^2
Explanation:
The equation of the forces acting on the box in the direction parallel to the slope is:
(1)
where
is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity,
being the angle of the incline
is the frictional force, with
being the coefficient of kinetic friction, N being the normal reaction of the plane
a is the acceleration
The equation of the force along the direction perpendicular to the slope is

where
is the component of the weight in the direction perpendicular to the slope. Solving for N,

Substituting into (1), solving for a, we find the acceleration:

Answer:
a) The exit temperature is 430 K
b) The inlet and exit areas are 0.0096 m² and 0.051 m²
Explanation:
a) Given:
T₁ = 127°C = 400 K
At 400 K, h₁ = 400.98 kJ/kg (ideal gas properties table)
The energy equation is:

For a diffuser, w = Δp = 0
The diffuser is adiabatic, q = 0
Replacing:

Where
V₁ = 250 m/s
V₂ = 40 m/s
Replacing:

Using tables, at 431.43 kJ/kg the temperature is 430 K
b) The inlet area is:

The exit area is:
